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4 years ago

(✓2÷✓3)^5 *(6÷7)^2 simplify

Chemistry

1 answer:

OlgaM077 [116]4 years ago

3 0

0.266611128466 is the answer I got when I typed it into a calculator.

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The osmotic pressure of an aqueoussolution of urea at 300 K is

den301095 [7]

Answer: The freezing point of solution is -0.09°C

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=imRT$

where,

$\pi$ = osmotic pressure of the solution = 120 kPa

i = Van't hoff factor = 1 (for non-electrolytes)

m = concentration of solute in terms of molality = ?

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

T = temperature of the solution = 300 K

Putting values in above equation, we get:

$120kPa=1\times m\times 8.31\text{ L kPa }mol^{-1}K^{-1}\times 300K\\\\m=0.05m$

To calculate the depression in freezing point, we use the equation:

$\Delta T=i\times K_f\times m$

where,

i = Vant hoff factor = 1 (for non-electrolytes)

$K_f$ = molal freezing point depression constant = 1.86°C/m

m = molality of solution = 0.05 m

Putting values in above equation, we get:

$\Delta T=1\times 1.86^oC/m\times 0.05m\\\\\Delta T=0.09^oC$

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

The equation used to calculate freezing point of solution is:

$\Delta T=\text{freezing point of water}-\text{freezing point of solution}$

where,

$\Delta T$ = Depression in freezing point = 0.09 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

$0.09^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-0.09^oC$

Hence, the freezing point of solution is -0.09°C

4 0

3 years ago

The process by which nitrogen gas is converted to a usable form called nitrogen what

polet [3.4K]

The process is called, Fixation

6 0

4 years ago

What are the two half-reactions that occur in this electroplating process. Be sure to include the states of the elements or ions

Serhud [2]

This is rather a case of purification of impure copper or extraction of Cu from its alloy. You need to place the impure copper rod on the positive electrode (Anode) usualyy made of carbon rod, whereby oxidation reaction takes place: Cu (s) -------> Cu2+ (aq) + 2e- That is to say the impure cooper dissolves into solution. The copper (II) ions move to the negative electrode (cathode) usually made of pure copper rod. At the cathode, the Cu2+ ions are reduced : Cu2 (aq)+ + 2e- -----> Cu(s). That is to say the copper (II) ions are deposited as solid copper atoms onto the cu-rod electrode. In this way impure copper is deposited as pure copper onto the copper cathode

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4 years ago

How much heat is required to increase the temperature of 198.5 grams of water from 25.0

velikii [3]

5.27*10^4 (52,700.)

4 0

4 years ago

Which best describes the purpose of a controlled expierment

Dmitrij [34]

Answer:

is to examine that whether the other variables causes a change in another. The experimental setup of controlled experiments are designed to test the hypotheses. ... It allows to change more than one variable, on the condition that all other variables are controlled.

8 0

3 years ago