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Lesechka [4]
3 years ago
14

What term expresses the ratio of moles of reactants and products according to the coefficients in the balanced chemical equation

? A) mole ratio B) reactant ratio C) product ratio D) yield ratio E) none of the above
Chemistry
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

A) mole ratio

Explanation:            

<em>A mole ratio</em>, also known as a mole-to-mole ratio, <em>is ​the ratio between the amounts in moles of one reactant/product to the moles of the other reactant/product. </em>This ratio is determined considering the coefficients in a balanced chemical equation. This ratio is used in chemical problems as a conversion factor between the compounds involved in the reaction.

I hope you find this information useful and interesting! Good luck!

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Answer:

NaCL + H2O

Explanation:

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When mixed, solutions of silver nitrate, AgNO3, and sodium sulfate, Na2SO4, form a precipitate of silver sulfate, Ag2SO4. The ba
Maslowich

Answer:

2 AgNO3 + Na2SO4 → Ag2SO4 + 2 NaNO3

Explanation:

The general schemefor a reaction is given as;

Reactants --> Products

In this question, the reactants are AgNO3 and Na2SO4. The product is Ag2SO4.

The equation is given as;

AgNO3 + Na2SO4 --> Ag2SO4

The other poduct formed in this reaction is NaNO3.

The full reaction is given as;

AgNO3 + Na2SO4 --> Ag2SO4 + NaNO3

The above reaction is not balanced because there are unequal number of atoms of the elements on both sides of the reaction.

The balanced equation is given as;

2 AgNO3 + Na2SO4 → Ag2SO4 + 2 NaNO3

In this equation, there are equal number of moles of the atoms on both sides.

3 0
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What is a period on the Periodic Table? *
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Answer:

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8 0
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Furkat [3]

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The answer should be A

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7 0
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Read 2 more answers
A 75.0 g sample of dinitrogen monoxide is confined in a 3.q L vessel. What is the pressure( in atm) at 115 celsius
Nonamiya [84]
Data Given:
                  Pressure  =  P  =  ?

                  Volume  =  V  =  3.0 L

                  Temperature  =  T  =  115 °C + 273  =  388 K

                  Mass  =  m  =  75.0 g

                  M.mass  =  M  =  44 g/mol

Solution:
              Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
                                      P V  =  n R T
Solving for P,
                                      P  =  n R T / V      ------ (1)
Calculating Moles,
                                      n  =  m / M

                                      n  =  75.0 g / 44 g.mol⁻¹

                                      n  =  1.704 mol

Putting Values in Eq. 1,

                    P  =  (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L

                    P  =  18.08 atm
7 0
3 years ago
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