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Alinara [238K]
2 years ago
6

Draw the bridged bromonium ion that is formed as an intermediate during the bromination of this alkene. Include hydrogen atoms,

nonbonding electrons, and formal charge(s) in your structure. The starting alkene is a 4 carbon chain with a double bond between carbons 2 and 3. The substituents on the alkene are on opposite sides of the alkene. This reacts with B r 2 to give the intermediate ion.
Chemistry
1 answer:
vivado [14]2 years ago
4 0

Answer:

See explanation and image attached

Explanation:

The reaction of bromine molecule with an alkene passes through a bridged intermediate known as the brominium ion.

It is a cyclic intermediate that contains a positively charged bromine ion as i have shown in the image attached.

The brominium ion is first formed during the bromininaton of alkenes.

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List the protons, neutrons, and electrons for Ge2+<br> Please hurry
Nady [450]

Answer:

32, 30 and 41

Explanation:

The problem here is to find the number of:

    Protons, neutrons and electrons in Ge²⁺

In this ion,

   We must understand that for a net positive charge to remain on an atom, the number of protons must be greater than the number of electrons.

Ge is Germanium with atomic number of 32;

So the number of protons is 32

Since the atom has lost two electrons;

  Number of electrons now is 32  - 2 = 30

Number of neutrons is 41 from the periodic table.

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2 years ago
Acetylene gas (C2H2) burns completely in the presence of oxygen gas (O2) to yield carbon dioxide
Luda [366]

A. The balanced equation for the reaction is

2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O

B. The volume of the oxygen gas required to burn 0.700 L of acetylene gas is 1.75 L

C. The volume of carbon dioxide gas produced is 1.4 L

D. The volume of water vapor produced is 0.7 L

<h3>A. Balanced equation </h3>

The balanced equation for the reaction between acetylene gas (C₂H₂) and oxygen gas (O₂) is given below

2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O

<h3>B. How to determine the volume of oxygen </h3>

2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O

Since the reaction occurred at standard temperature and pressure, we can thus say that:

From the balanced equation above,

2 L of C₂H₂ reacted with 5 L O₂.

Therefore,

0.7 L of C₂H₂ will react with = (0.7 × 5) / 2 = 1.75 L of O₂

Thus, 1.75 L of O₂ is needed for the reaction

<h3>C. How to determine the volume of carbon dioxide </h3>

2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O

From the balanced equation above,

2 L of C₂H₂ reacted to produce 4 L of CO₂

Therefore,

0.7 L of C₂H₂ will react to produce = (0.7 × 4) / 2 = 1.4 L of CO₂

Thus, 1.4 L of CO₂ were produced

<h3>D. How to determine the volume of water. </h3>

2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O

From the balanced equation above,

2 L of C₂H₂ reacted to produce 2 L of H₂O

Therefore,

0.7 L of C₂H₂ will also react to produce 0.7 L of H₂O

Thus, 0.7 L of H₂O was produced

Learn more about stoichiometry:

brainly.com/question/14735801

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