Lesson 9 functions, equations, and graphs unit test part 1

8:2 in its simplest form

VMariaS [17]

Answer:

4:1

Step-by-step explanation:

just divide by 2

4 0

3 years ago

Is (x+4)^2 equivalent to 2x^2+8x+8? Explain or show your reasoning.

Zolol [24]

Answer:

It's wrong because the y intercepts are different

Step-by-step explanation:

The box method is OP for these kind of questions

If I don't do a good job explaining it then I reccomend you consult the internet

8 0

3 years ago

Identify the effect on the graph of replacing f(x) by f(x - h)

Tresset [83]

Given:

Replace f(x) by f(x - h).

To find:

The effect on the graph of replacing f(x) by f(x - h).

Solution:

Horizontal shift is defined as:

If the graph f(x) shifts h units left, then f(x+h).

If the graph f(x) shifts h units right, then f(x-h).

Where, h is a constant that represents the horizontal shift.

In the given problem f(x) is replaced by f(x - h) and we need to find the effect on the graph.

Here, we have x-h in place of x.

Therefore, the graph of f(x) shifts h units right to get the graph of f(x-h).

4 0

3 years ago

How to do this question plz answer

harina [27]

9514 1404 393

Answer:

300

Step-by-step explanation:

There are 25 ways to select the first student. After that student is removed from the selection pool for the second student, there are 24 ways to select the second student. This gives 25·24 = 600 ways to select 2 students in a particular order.

Since we don't care about the order, we can divide this number by the number of ways two students can be ordered: AB or BA, 2 ways.

600/2 = 300

There are 300 ways to pick a combination of two students from 25.

__

Additional comments

This sort of selection (2 out of 25) has a formula for it, and an abbreviation for the formula.

"n choose k" can be written nCk or C(n, k)

The function is a ratio of factorials:

nCk = n!/(k!(n-k)!)

If you can typeset this, it is written ...

$\displaystyle\binom{n}{k}=\frac{n!}{k!\cdot(n-k)!}$

This is different from the formula for the number of permutations of n things taken k at a time. That would be written nPk or P(n, k) = n!/(n-k)!.

5 0

2 years ago

Read 2 more answers

3. Factory farming funk - The US Environmental Protection Agency (EPA) recently reported that confined animal feeding operations

Vikentia [17]

Answer:

Step-by-step explanation:

Hello!

There was a survey made in Michigan asking the residents if they were in favor of or against the creation of standards to limit pollution by CAFOs.

Using the results of the survey the student that conducted it estimated the population proportion of Michigan residents that are in favor of the creation of standards to limit pollution by CAFOs.

The calculated 95% CI is [0,7752; 0,8248]

Interpretation: With a 95% confidence level you'd expect that the interval [0,7752; 0,8248] will include the true population proportion of Michigan residents that are in favor of the creation of standards to limit pollution by CAFOs.

i.e. If you were to construct 100 confidence intervals, you'd expect 95 of them to contain the true value of the proportion of Michigan residents that are in favor of the creation of standards to limit pollution by CAFOs.

With this in mind:

Consider all of the following statements and determine which among them is incorrect

1) There is a 95% probability that the actual percent of Michigan residents in favor of pollution standards is between 77.52% and 82.48%. INCORRECT

2) Approximately 95% of MSU students favor pollution standards at a rate of 77.52% and 82.48%. INCORRECT

The confidence level is the probability that the interval will contain the true value of the parameter of interest and the bonds of the interval indicate the possible range of that parameter.

Also in 1) The parameter is not defined correctly, and in 2) the population of interest is incorrect.

3) If this study were repeated many times, we'd expect approximately 95% of future confidence intervals to contain the true rate at which Michigan residents favor the creation of pollution standards. CORRECT

4) With 95% confidence, we estimate the true rate at which Michigan residents favor the creation of pollution standards to be between 77.52% and 82.48%. CORRECT

I hope it helps!

6 0

3 years ago