A math book contains 404 pages, a science

Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr

Minchanka [31]

Answer:

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". The margin of error is the range of values below and above the sample statistic in a confidence interval. Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". [tex]p_1$ represent the real population proportion for 1

$\hat p_1 =0.768$ represent the estimated proportion for 1

$n_1=92$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =0.646$ represent the estimated proportion for 2

$n_2=95$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

$ME= \frac{0.2753-(-0.0313)}{2}=0.1533$

And we know that the margin of erro is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

We have all the values except the value for $z_{\alpha/2}$

So we can find it like this:

$0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}$

And solving for $z_{\alpha/2}$ we got:

$z_{\alpha/2}=2.326$

And we can find the value for $\alpha/2$ with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98$ or 98%

7 0

2 years ago

A car travels 20 1/2 miles in 2/3 of an hour. What is the average speed, in miles per hour, of thr car?

zmey [24]

Answer:

27.33333... mph

Step-by-step explanation:

Find 1/3 of 20 1/2: 1/3*41/2=41/6

That equals 6.83333...

Now add 20 1/2 and 6.83333 = 27.3333...

Therefore, 27.33333... mph

3 0

2 years ago

If a pair of shoes cost $40 and they are on sale for 30% off how much would they be

yulyashka [42]

multiply 40 by 30% to find the discount then subtract

40 * 0.30 = 12

40-12 = 28

they would cost $28

6 0

3 years ago

Can someone be my friend please!!!

KIM [24]

Answer:

no problem sure!

Step-by-step explanation:

;D

4 0

2 years ago

jamie and emily are married and make a total annual gross pay of 91,500. Use the table below to calculate their total and federa

olya-2409 [2.1K]

Their total income tax is $10,980.

<h3><u /></h3><h3><u>Percentages</u></h3>

Given that Jamie and Emily are married and make a total annual gross pay of $91,500, to determine their total income tax at 12% rate, the following calculation must be performed:

91500 x 12/100 = X
91500 x 0.12 = X
10980 = X

Therefore, their total income tax is $10,980.

Learn more about percentages in brainly.com/question/1691136

8 0

2 years ago