Answer: The percent yield of lithium chloride if a reaction starts with 20.0 g lithium hydroxide and yields 6.00 g lithium chloride is 17.2 %
Explanation:
The balanced chemical reaction is
To calculate the moles, we use the equation:
a) moles of
b) moles of
According to stoichiometry :
1 mole of produces = 1 mole of
Thus 0.83 moles of produce= of
Mass of
The theoretical yield of = 34.9 g
The experimental yield of ethanol = 6.00 g
Now we have to calculate the percent yield of ethanol.
Therefore, the percent yield is, 17.2 %
Answer:
60 x 10^6
Explanation:
12 x 5 = 60
add the exponents 4+2 so 10^6
60 x 10^6 is the answer
Answer:
The first part of his theory states that all matter is made of atoms, which are indivisible. The second part of the theory says all atoms of a given element are identical in mass and properties. The third part says compounds are combinations of two or more different types of atoms.
Explanation:
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10 electrons in an atom can have each of the 3d quantum number or sublevel designations.
<h3>What are four quantum numbers?</h3>
Quantum numbers are used to characterize the values of conserved quantities in a quantum system's dynamics in both quantum physics and chemistry.
1) The "n" sign refers to the principal quantum number. It shows how many shells there are.
2) The "l" sign indicates the azimuthal quantum number. It gives the form of the orbitals and their angular momentum. 0 to n-1 make up its range.
3) "" stands for the magnetic quantum number. It serves as a cue for spatial orientation. The range of it is -l to +l.
4) Spin quantum number, represented by the symbol "". It shows how the electron is spinning.
Learn more about quantum numbers here:
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The balanced reaction would be as follows:
<span>3NaOH + H3PO4 --> Na3PO4 + 3H20
We are given the concentration and the amount of the reactants to be used. We use these values for the calculations as follows:
</span><span>How many mL of .225 M NaOH will react with 4.568g H3PO4?
4.568 g (1 mol / 98 g) ( 3 mol NaOH / 1 mol H3PO4 ) ( 1 L / .225 mol NaOH ) = 0.621 L or 621 mL of .225 NaOH</span>