1- first law
2- third law
3- first law
4- second law
5- third law
6- second law
Answer:
In an elastic collision, the total kinetic energy is conserved, while in an inelastic collision, it is not
Explanation:
Let's define the two types of collision:
- Elastic collision: an elastic collision is a collision in which:
1) the total momentum of the system is conserved
2) the total kinetic energy of the system is conserved
Typically, elastic collisions occur when there are no frictional forces acting on the objects in the system, so that no kinetic energy is lost into thermal energy. An example of elastic collision is the collision between biliard balls.
- Inelastic collision: an inelastic collision is a collision in which:
1 ) the total momentum of the system is conserved
2) the total kinetic energy of the system is NOT conserved
In an elastic collision, part of the total kinetic energy is lost (=converted into thermal energy) due to the presence of frictional forces. An example of inelastic collision is the accident between two cars, in which part of the energy is converted into heat.
Answer:
28 cm and 32 cm
Explanation:
1. The spring pendulum hangs vertically, oscillates harmonic with amplitude 2cm and angular frequency 20 rad/s. The natural length of
a spring is 30cm. What is the minimum and maximum length of the spring during the oscillation? Take g = 10m/s2.
As the amplitude is 2 cm and the natural length is 30 cm. So, it oscillates between 30 -2 = 28 cm to 30 + 2 = 32 cm.
So, the minimum length is 28 cm and the maximum length is 32 cm.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The workdone is ![W = -177.275J](https://tex.z-dn.net/?f=W%20%3D%20-177.275J)
Explanation:
From the question we are told that
The initial Volume is ![Vi = 0.160 L](https://tex.z-dn.net/?f=Vi%20%3D%200.160%20L)
The final volume is ![V_f = 0.510L](https://tex.z-dn.net/?f=V_f%20%3D%200.510L)
The external pressure is
Generally the change in volume is
![\Delta V = V_f - V_i](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20V_f%20-%20V_i)
Substituting values we have
![\Delta V = 0.510 -0.160](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%200.510%20-0.160)
![= 0.350L](https://tex.z-dn.net/?f=%3D%200.350L)
Generally workdone is mathematically represented as
![W = -P \Delta V](https://tex.z-dn.net/?f=W%20%3D%20-P%20%5CDelta%20V)
W is negative because the working is done on the environment by the system which is indicated by volume increase
Substituting values
![W = - 5* 0.350](https://tex.z-dn.net/?f=W%20%3D%20-%205%2A%200.350)
![= -1.75 \ L \ \cdot atm](https://tex.z-dn.net/?f=%3D%20-1.75%20%5C%20L%20%5C%20%5Ccdot%20atm)
Now ![1 \ L \cdot atm = 101.3J](https://tex.z-dn.net/?f=1%20%5C%20%20L%20%5Ccdot%20atm%20%3D%20101.3J)
Therefore ![W = -1.75* 101.3](https://tex.z-dn.net/?f=W%20%3D%20-1.75%2A%20101.3)
![= -177.275J](https://tex.z-dn.net/?f=%3D%20-177.275J)