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Dmitrij [34]
4 years ago
5

A compass is a magnet and Earth is a magnet. How does the magnetism of a compass work with the

Physics
1 answer:
Doss [256]4 years ago
7 0
The compass magnet aligns itself with the earths magnetic field.
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A 5 .0kg cart is moving horizontaly at 6 .0m/s in order to change its speed to 10m/s the net work done on the cart must be
ahrayia [7]

Answer:

the net work done on the cart is 160 J.

Explanation:

Given;

mass of the cart, m = 5.0 kg

initial velocity of the cart, u = 6 m/s

final velocity of the cart, v = 10 m/s

The net work done on the cart is equal to change in average kinetic energy of the cart;

W = K.E = \frac{1}{2} m(v^2-u^2)\\\\W = \frac{1}{2} \times 5(10^2-6^2)\\\\W = 160 \ J

Therefore, the net work done on the cart is 160 J.

8 0
3 years ago
Select all the correct answers.
kkurt [141]

Answer:

tge tendence to atract electrons

Explanation:

7 0
3 years ago
A 4.0 kg shot put is thrown with 30 N of force. What is its acceleration?
weeeeeb [17]

7.5 m/s

a = F ÷ m

a = (30 N) ÷ (4.0 kg)

a = 7.5 m/s2

7 0
3 years ago
Light of wavelength O is passed through a diffraction grating with N lines/meter and then lands on a screen a distance L from th
rodikova [14]

Condition for diffraction

dsin\theta = m\lambda

Where

a = Distance between slits

m = Order of the fringes

\lambda = Wavelength

\theta = At the angle between the ray of light and the projected distance perpendicular between the two objects

For small angles

sin\theta = \approx tan\theta

Where

tan\theta = \frac{Y}{L}

Where L is the distance between the slits and Y the length of the light.

Replacing we have

d\frac{Y}{L} = \lambda m

Y = \frac{m\lambda L}{d}

The distance between slits d can be expressed also as d= \frac{L}{N} Where N is the number of the fringes, then

Y_n = mN\lambda L

Similarly when there is added a new Fringe we have the change of the distance would be :

Y_{n+1} = (m+1)N\lambda L

Linear distance between fringes is

\Delta Y = \Delta Y_{m+1}-Y_m

\Delta Y = (m+1)N\lambda L - mN\lambda L

Therefore the answer is

\Delta Y = N\lambda L

8 0
3 years ago
A 10-N force is needed to move an object with a constant velocity of 5.0 m/s. What power must be delivered to the object by the
vagabundo [1.1K]

The power that must be delivered to the object by the force is 50 W

Power is defined as the rate of doing work. The power of an object in relation to the force and velocity is given by the following equation:

Power (P) = Force (F) × velocity (v)

P = F × v

From the question given above, the following data were obtained:

  • Force (F) = 10 N
  • Velocity (v) = 5 m/s
  • Power (P) =?

P = F × v

P = 10 × 5

<h3>P = 50 W </h3>

Thus, the power that must be delivered to the object by the force is 50 W

Learn more on power: brainly.com/question/19539420

5 0
2 years ago
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