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Dmitrij [34]
3 years ago
5

A compass is a magnet and Earth is a magnet. How does the magnetism of a compass work with the

Physics
1 answer:
Doss [256]3 years ago
7 0
The compass magnet aligns itself with the earths magnetic field.
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PLEASE HURRY Take 40 points.please just look at the picture.​
Fynjy0 [20]

Answer:

It you get a sushi for work, for a party, then it leads to people being happy, as an independant variable

It is changing the molecular structure of a protein

Explanation:

7 0
3 years ago
What is the volume for a cabinet that measures 1.20m by 5m by 75cm
zavuch27 [327]

Answer:

45000cm2(cuarenta y cinco mil centimetros al cuadrado).

Explanation:

porque el volumes es igual a el área de la base por la altra

5 0
3 years ago
An electron moves at 0.130 c as shown in the figure (Figure 1). There are points: A, B, C, and D 2.10 μm from the electron.
Olegator [25]

Hi there!

We can use Biot-Savart's Law for a moving particle:
B= \frac{\mu_0 }{4\pi}\frac{q\vec{v}\times \vec{r}}{r^2 }

B = Magnetic field strength (T)
v = velocity of electron (0.130c = 3.9 × 10⁷ m/s)

q = charge of particle (1.6 × 10⁻¹⁹ C)

μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)

r = distance from particle (2.10 μm)

There is a cross product between the velocity vector and the radius vector (not a quantity, but specifies a direction). We can write this as:

B= \frac{\mu_0 }{4\pi}\frac{q\vec{v} \vec{r}sin\theta}{r^2 }

Where 'θ' is the angle between the velocity and radius vectors.

a)
To find the angle between the velocity and radius vector, we find the complementary angle:

θ = 90° - 60° = 30°

Plugging 'θ' into the equation along with our other values:

B= \frac{\mu_0 }{4\pi}\frac{q\vec{v} \vec{r}sin\theta}{r^2 }\\\\B= \frac{(4\pi *10^{-7})}{4\pi}\frac{(1.6*10^{-19})(3.9*10^{7}) \vec{r}sin(30)}{(2.1*10^{-5})^2 }

B = \boxed{7.07 *10^{-10} T}

b)
Repeat the same process. The angle between the velocity and radius vector is 150°, and its sine value is the same as that of sin(30°). So, the particle's produced field will be the same as that of part A.

c)

In this instance, the radius vector and the velocity vector are perpendicular so

'θ' = 90°.

B= \frac{(4\pi *10^{-7})}{4\pi}\frac{(1.6*10^{-19})(3.9*10^{7}) \vec{r}sin(90)}{(2.1*10^{-5})^2 } = \boxed{1.415 * 10^{-9}T}

d)
This point is ALONG the velocity vector, so there is no magnetic field produced at this point.

Aka, the radius and velocity vectors are parallel, and since sin(0) = 0, there is no magnetic field at this point.

\boxed{B = 0 T}

3 0
2 years ago
one parent is heterozygous dominant for dimples and the other parent is homozygous recessive.use the letter H and what is the pe
user100 [1]
Using a punnet square, 
    h    h 
H Hh Hh
h hh  hh 

The offspring will be 50% Heterozygous dominant and 50% homozygous recessive. 
3 0
3 years ago
Read 2 more answers
Please who can give me the definition of density in terms of Archimedes principle.​
VladimirAG [237]

\large\bold{\underline{\underline{Answer:-}}}

  • The weight of the fluid displaced is equal to the buoyant force on a submerged object. The mass divided by the volume thus determined gives a measure of the average density of the object.
8 0
2 years ago
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