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Pavlova-9 [17]
2 years ago
14

My buddy and I have just finished a dive to 15 metres/50 feet for 60 minutes. We want to return to the same site and depth and s

tay another 60 minutes. We can ______________________ to see about how long we have to remain at the surface to have enough no stop time. (choose all that apply)
Physics
1 answer:
marishachu [46]2 years ago
7 0

Answer:

1) Periodically check the no stop or NDL time on their computers

2) The dive computer planning mode can be used if available

3) Make use of a dive planning app

4) Check data from the RDP table or an eRDPML

Explanation:

The no stop times information from the computer gives the no-decompression limit (NDL) time allowable which is the time duration a diver theoretically is able to stay at a given depth without a need for a decompression stop

The dive computer plan mode or a downloadable dive planning app are presently the easiest methods of dive planning

The PADI RDP are dive planners based on several years of experience which provide reliable safety limits of depth and time.

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bulgar [2K]

The table is:

t(s)  vx(m/s)

0     0

10    23

20   46

30   69

a) from the data in the table, we observe that the acceleration is constant (because the rate of change in velocity is the same for each time interval of 10 seconds), so we can choose just one interval and calculate the acceleration as the ratio between the change in velocity and the change in time. Taking the first interval, we find

a=\frac{\Delta v_x}{\Delta t}=\frac{23 m/s-0}{10s -0}=2.3 m/s^2


b) To find the jet's acceleration in g's, we just need to divide the acceleration in m/s^2 by the value of g, the acceleration of gravity (9.81 m/s^2), so we find

a_g=\frac{a}{g}=\frac{2.3 m/s^2}{9.8 m/s^2}=0.23 g


c) the wheels leave the ground when the jet reaches its take-off velocity, which is 82 m/s.

At t=0s, the velocity of the jet is 0. We know that the acceleration is constant (a=2.3 m/s^2), so we can find the time t at which the jet reaches a velocity vf=82 m/s by using the equation

v_f = v_i +at

Re-arranging and substituting numbers, we find

t=\frac{v_f}{a}=\frac{82 m/s}{2.3 m/s^2}=35.65 s

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Answer:

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