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2 years ago

10

A point charge of -3.0 x 10-5C is placed at the origin of coordinates. Find the electric field at the point 3. r= 50 m on the x-

axis

1 answer:

Snezhnost [94]2 years ago

4 0

Answer: -5×10-3

Explanation:

E=kq/r

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When three identical bulbs of 60W,200V rating are connected in series at a 200V supply the power drawn by them will be?

Law Incorporation [45]

Answer:

P = 180 [w]

Explanation:

To solve this problem we must use ohm's law, which is defined by the following formula.

V = I*R & P = V*I

where:

V = voltage = 200[volts]

I = current [amp]

R = resistance [ohm]

P = power [watts]

Since the bulbs are connected in series, the powers should be summed

P = 60 + 60 + 60

P = 180 [watts]

Now we can calculate the current

I = 180/200

I = 0.9[amp]

Attached is an image where we see the three bulbs connected in series, in the circuit we see that the current is the same for all the elements connected to the circuit.

And the power is defined by P = V*I

we know that the voltage is equal to 200[V], therefore

P = 200*0.9

P = 180 [w]

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2 years ago

Red light from three separate sources passes through a diffraction grating with 5.60×105 slits/m. The wavelengths of the three l

shtirl [24]

Answer:

I can help

Explanation:

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3 years ago

The specific heat of granite is 800 J/(kg·°C). How much heat does it take to raise 1 kg of granite 4°C?

Triss [41]

Q=mcΔt
Q= 1kg * 800J/kg°C*4°C
Q= 3200J

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3 years ago

Larger animals use proportionately less energy than smaller animals; that is, it takes less energy per kg to power an elephant t

marin [14]

Answer:

Part a)

$Q = 952 cal/day$

Part b)

$P = 46 Watt$

Part c)

$\Delta P = 54 W$

Explanation:

As we know that 5000 kg African elephant requires 70,000 Cal for basic needs per day

so we will have

$m = 5000 kg$

$Q = 70,000 Cal$

so we have energy required per kg

$E = \frac{70,000}{5000}$

$E = 14 cal/kg$

Part a)

now we know that per kg the energy required will be same

so we have mass of the human is 68 kg

so energy required per day is given as

$Q = 68 \times 14$

$Q = 952 cal/day$

Part b)

Resting power is the rate of energy in Joule required per sec

so it is given as

$P = \frac{952 \times 4186}{24\times 3600}$

$P = 46 Watt$

Part c)

resting power given in the book is

$P' = 100 W$

so this is less than the power given

$\Delta P = 100 - 46$

$\Delta P = 54 W$

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3 years ago

Do noble gases lose or gain electrons to get a full valence shell?

alexdok [17]

They don't lose OR gain electrons as they've already achieved the octet rule and have 8 valence electronsn

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3 years ago