Answer:
When N is an even number, use the first equation in the matrix. When N is negative use the second equation.
Step-by-step explanation:
n = 6 | 6/2 = 3
n=5 | 3(5)+1 = 16
Answer:
Then the total area is 116 cm^2 which agrees with answer D
Step-by-step explanation:
Notice we need to calculate the area of two rectangles (one larger at the bottom and a smaller one on top)
The Area of a rectangle is the product: base x height
In our case :
Area of Big rectangle = 12 cm x 7 cm = 84 cm^2
Area of smaller rectangle = 8 cm x 4 cm = 32 cm^2
Then the total area is: 84 cm^2 + 32 cm^2 = 116 cm^2
Answer:
What is the height of each triangle side?
Step-by-step explanation:
The area of the triangle formed by his path is 34971.98 ft sq to the nearest hundredth.
<h3>What is the Heron's formula?</h3>
The Heron's formula is given as;
√s(s-a)(s-b)(s-c)
where s is half the perimeter of the triangle
WE have been given that horse gallops 200ft, turns and trots 350ft, turns again and travels 410ft to return to the point he started from.
Perimeter of the triangle is given as = 200 + 350 + 410 = 960 ft
Semi perimeter = 960 ft/ 2 = 480 ft
Area = √s(s-a)(s-b)(s-c)
Area = √480 (480 -200)(480 -350)(480 -410)
Area = √480 (280)(130)(70)
Area = √480 (2548000)
Area = 34971.98
The area of the triangle formed by his path is 34971.98 ft sq to the nearest hundredth.
Learn more about the Heron's formula;
brainly.com/question/20934807
#SPJ1
The complete question is
A horse gallops 200ft, turns and trots 350ft, turns again and travels 410ft to return to the point he started from. What is the area of the triangle formed by his path? round to the nearest hundredth.
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = 
= 15°c
The final temperature = 
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( - )
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
