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3 years ago

Part A

Chemistry

1 answer:

den301095 [7]3 years ago

3 0

Answer:

$n_{Cl_2}=0.3molCl_2$

Explanation:

Hello there!

In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:

$n_{Cl_2}=0.6molNaCl*\frac{1molCl_2}{2molNaCl}$

So we cancel out the moles of NaCl to obtain:

$n_{Cl_2}=0.3molCl_2$

Best regards!

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Answer:

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