Answer:
A)
Cl + O3 --> ClO + O2
2ClO --> ClOOCl
ClOOCl --> 2 Cl + O2
B)
Cl2 + 4O3 -> 2 ClO + 5O2
Explanation:
Step 1: Chlorine atoms react with ozone (O3) to form chlorine monoxide and molecular oxygen
Cl + O3 --> ClO + O2
Step 2: Chlorine monoxide molecules combine to form ClOOCl gas
2ClO --> ClOOCl
Step 3: ClOOCl absorbs sunlight and breaks into chlorine atoms and molecular oxygen
ClOOCl --> 2 Cl + O2
B) Overall Balanced equation
Cl2 + 4O3 -> 2 ClO + 5O2
<u>Answer:</u> The percent composition of hydrogen in the sample is 15.22 %
<u>Explanation:</u>
We are given:
Mass of hydrogen = 7 grams
Mass of nitrogen = 32 grams
Mass of carbon = 7 grams
Total mass of the sample = 7 + 32 + 7 = 46 grams
To calculate the percentage composition of hydrogen in sample, we use the equation:
Mass of sample = 46 g
Mass of hydrogen = 7 g
Putting values in above equation, we get:
Hence, the percent composition of hydrogen in the sample is 15.22 %
A hypothesis
-Can be tested
-Is a prediction about the expected outcome of an experiment
-Must be stated in a form that can be either proven or disproven
Your answer is D: All of the above are true
When a cell uses chemical energy to perform work it couples exergonic reaction with endergonic reaction.
1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution. Details about molarity can be found below.
<h3>How to calculate molarity?</h3>
The number of moles of a solution can be calculated by multiplying the molarity of the solution by its volume. That is;
no of moles = molarity × volume
According to this question, a solution has a molarity of 8.20M and volume of 125 mL of solution.
no of moles = 8.20 × 0.125
no of moles = 1.025moles
Therefore, 1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution.
Learn more about number of moles at: brainly.com/question/14919968
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