All categories

2 years ago

How many mols of a 3M NaOH solution are in 1L of the solution?

1 answer:

Alex2 years ago

6 0

To calculate this, we need the Molarity formula. This formula tell us that Molarity, which is a concentration unit, is equal to the number of moles divided by the volume. In this question we already have the Molarity and the Volume, so let's build our equation:

C = n/V (You can see Molarity with the letter "C" because it means concentration)

3 = n/1

n = 1 * 3

n = 3 moles of NaOH

You might be interested in

I need helpppppppppppppppppppppppppppppppppppp

11Alexandr11 [23.1K]

Answer:

Explanation:

Carbon dioxide in the air

7 0

3 years ago

Read 2 more answers

Increasing the volume of a given amount of gas at constant temperature causes the pressure to decrease because

mestny [16]

Because the molecules are more spread apart.

(gas spread)

5 0

3 years ago

Read 2 more answers

Why is burning fossil fuels a problem?

valina [46]

Answer:

it's harmful

Explanation:

it's harmful to our environment it can endanger our planet and endangered animal species it can also kill lots of plants and we have a hard time burning fossil fuels with limited factories which costs a lot of money.

8 0

3 years ago

Read 2 more answers

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m

Bond [772]

Answer:

$m_{H_2O}=4.86gH_2O$

Explanation:

Hello,

In this case, the described chemical reaction is:

$C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O$

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

$n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6$

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

$n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6$

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

$m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O$

Best regards.

3 0

3 years ago

To freeze/melt a substance, does the substance have to absorb it release heat?

Wewaii [24]

Answer: All solids absorb heat as they melt to become liquids.

Explanation:

5 0

4 years ago