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3 years ago

Define ohms law .......

Physics

1 answer:

Sveta_85 [38]3 years ago

6 0

Answer:

Ohm's Law is a formula used to calculate the relationship between voltage, current and resistance in an electrical circuit. To students of electronics, Ohm's Law (E = IR) is as fundamentally important as Einstein's Relativity equation (E = mc²) is to physicists.

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An ideal blackbody is an object that __________.a. absorbs most of the energy that strikes it. b. only absorbs energy at ultravi

STALIN [3.7K]

Answer:

c. absorbs all the energy that strikes it.

Explanation:

<em>An ideal black body is an object that absorbs every light energy (irrespective of the wavelength and direction) that strikes it without reflecting any in return. </em>

<em>Such objects or bodies usually appear perfectly black and will only emit radiation when heated to a very high temperature.</em>

6 0

3 years ago

Two long, parallel wires are attracted to each other by a force per unit length of 305 µN/m. One wire carries a current of 25.0

kykrilka [37]

To solve this problem we will use the concepts related to the electromagnetic force related to the bases founded by Coulumb, the mathematical expression is the following as a function of force per unit area:

$\frac{F}{L} = \frac{kl_1l_2}{d}$

Here,

F = Force

L = Length

k = Coulomb constant

I =Each current

d = Distance

Force of the wire one which is located along the line y to 0.47m is $305*10^{-6}N/m$ then we have

$l_2 = \frac{F}{L} (\frac{d}{kl_1})$

$l_2 = (305*10^{-6}N/m)(\frac{0.470m}{(2*10^{-7})(25A))})$

$l_2 = 28.67A$

Considering the B is zero at

$y = y_1$

$\frac{kI_2}{2\pi y} =\frac{kI_1}{2\pi y_1}$

$\frac{(4\pi*10^{-7})(28.67)}{2\pi (y_1)} = \frac{(4\pi *10^{-7})(25)}{2\pi (0.47-y_1)}$

$y_1 = 0.25m$

Therefore the value of y for the line in the plane of the two wires along which the total B is zero is 0.25m

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4 years ago

If a car increases its velocity from 1m/s to 3.6km/hr in 5 seconds what’s its acceleration

EleoNora [17]

Answer:

applying 1st eq of motion vf=vi+at here we have to find a=vf-vi/t , a= 1-1/5 , a=0/5 then we got a=0 here(vf value 3.6km/h is converted in standard unit 3.6×1000/3600 so we get vf=1m/s²

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3 years ago

How much work is done when 0.0050 c is moved through a potential difference of 9.0 v? use w = qv?

quester [9]

Answer:

0.045 J

Explanation:

The work done on a charge moving through a potential difference is given by

$W=q\Delta V$

where

W is the work done

q is the charge

$\Delta V$ is the potential difference

In this problem, we have

q = 0.0050 C is the charge

$\Delta V=9.0 V$ is the potential difference

Using the formula, we find the work done:

$W=(0.0050 C)(9.0 V)=0.045 J$

4 0

3 years ago

Read 2 more answers

As a 2-kg ball rolls down a ramp, the net force on it is 10 N. What is the acceleration?

evablogger [386]

That all depends on the direction of the force. If the force is parallel to the ramp, then the acceleration of the ball is 5 m/s^2. If the force isn't parallel to the ramp, then the acceleration is less.

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3 years ago

Define ohms law .......​

Define ohms law .......