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Mice21 [21]
3 years ago
11

Drag tiles to match each fraction, decimal, or percent to an equivalent fraction, decimal, or percent.

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0

Answer:

...

Step-by-step explanation:

1. 0.002

2. 308%

3. 2 6/10

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Need help with this question​
mestny [16]

Answer:

swag

Step-by-step explanation:

8 0
3 years ago
If f(x) = x+3 and g(x) = VX-1,<br> what is (fºg)(26)?
scZoUnD [109]

Answer:

26V + 2

Step-by-step explanation:

This is the same as saying f(g(x)), where x = 26

First, lets figure out what g(x) is equal to when x = 26

g(26) = V(26) - 1 = 26V - 1

Now we input 26V - 1 into f(x) for x

f(26V-1) = (26V-1) + 3 = 26V + 2

8 0
3 years ago
This is right or wrong, please anyone
BabaBlast [244]
Wrong,

You added when you were supposed to divide.

24/30 = 0.8


7 0
3 years ago
Read 2 more answers
Simplify to create an equivalent expression.<br> 8(a+2)+2(2+3a)=
Alchen [17]

Answer:

14a + 20

Step-by-step explanation:

8(a + 2) + 2(2 + 3a)

expand the bracket

8a + (8*2) + (2*2) + (2*3a)

8a + 16 + 4 + 6a

bring like terms together

8a + 6a + 16 + 4

14a + 20

3 0
3 years ago
Is my answer correct or no? <br> ---&gt; show explanation &amp; details if i am wrong!!!
neonofarm [45]

Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

∴ F is (0 , 0)

∵ The circle passes through point (7 , 0)

- The length of the radius of the circle is the distance between

   the center of the circle and a point on the circle

∴ r is the distance between points (0 , 0) and (7 , 0)

∴ r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7

∴ The length of the radius of the circle is 7 units

Let us find the distance between point (7 , -7) and the origin (0 , 0)

  • If the distance is equal to the radius of the circle, then the point is on the circle
  • If the distance is greater than the radius, then the point is outside the circle
  • If the distance is less than the radius, then the point is inside the circle

∵ The distance =  \sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}

∵ r = 7

∵ 7\sqrt{2} > 7

∴ The distance is greater than the radius of the circle

∴ Point (7 , -7) lies outside the circle

The correct answer is:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle

<em>Your answer is not correct, the correct answer is the 3rd answer</em>

3 0
3 years ago
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