On Aaron’s farm, 1/10 of the animals are cows, ⅖ of the animals are chickens,

Mathematics

1 answer:

Ray Of Light [21]3 years ago

6 0

Answer:

There are 5 pigs on Aaron's farm

Step-by-step explanation:

1. Start with 40 animals

2. 1/10 of the animals are cows, so divide 40 by 10 and you will find that 4 of the animals are cows

3. 2/5 of the animals are chickens, so multiple 40 by 2 to get 80 and then divide 80 by 5 and you will find that 16 of the animals are chickens

4. Subtract the 4 cows and 16 chickens from the 40 total animals and you find there are 20 more animals that are neither cows nor chickens

5. Of the 20 remaining animals, 1/4 are pigs, so divide 20 by 4 and you will find that there are 5 pigs

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The permutation is the way of choosing a set of objects from a larger set of objects in a specific sequence.

If we are choosing r number of objects, from n number of objects in a specific sequence, then we follow permutation, and it is given as:

nPr = n!{(n - r)!}.

In the question, we are asked to find the number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members.

Since the position is to be chosen in a specific order, we will follow permutation.

The number of positions to be chosen (r) = 2.

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Thus, the number of ways is given as:

nPr = n!{(n - r)!},

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Thus, the number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members is 240 ways. Computed using permutations.

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