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Vlad1618 [11]
2 years ago
11

Find X segment of circles

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
6 0

Answer:

x = 88/45

Step-by-step explanation:

square of tangent segment = produce of entire secant and segment of secant outside circle

(GH)² = GS × GW

(13)² = 9(5x + 9)

169 = 45x + 81

45x = 88

x = 88/45

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In a right triangle, the acute angles measure x + 15 and 2x degrees.
Valentin [98]

Answer:

50°

Step-by-step explanation:

x+15+2x=90

3x=90-15=75

x=75/3=25

one acute angle=25+15=40°

other acute angle=2×25=50°

7 0
3 years ago
Help i made it worth a lot of points
raketka [301]

Answer:

36x^6/y^10

Step-by-step explanation:

First evaluate the parentheses, 6x^3 x 6x^3 = 36x^6

y^5 x y^5 = y^10 ; remember m^k x m^r = m^k+r

final answer should be 36x^6/y^10

hope this helps :')

4 0
2 years ago
Read 2 more answers
A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o
Mandarinka [93]

Answer:

(a) Null Hypothesis, H_0 : \mu = 22 ounces  

    Alternate Hypothesis, H_A : \mu\neq 22 ounces

(b) The value of the test statistic is -2.687.

(c) The critical values are -1.96 and 1.96.

(d) We conclude that Reject H_0 since the value of the test statistic is less than the negative critical value.

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle.

He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

<em>Let </em>\mu<em> = average ounces of passion fruit juice used to fill each bottle.</em>

(a) So, Null Hypothesis, H_0 : \mu = 22 ounces     {means that the average of 22 ounces of passion fruit juice is used to fill each bottle}

Alternate Hypothesis, H_A : \mu\neq 22 ounces     {means that the average different from 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean weight of the passion fruit juice = 21.54 ounces

            \sigma = population standard deviation = 1.38 ounce

            n = sample of bottles = 65

So, <u><em>test statistics</em></u>  =  \frac{21.54-22}{\frac{1.38}{\sqrt{65} } }  

                               =  -2.687

(b) The value of z test statistics is -2.687.

(c) Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that Reject H_0 since the value of the test statistic is less than the negative critical value which means that the average different from 22 ounces of passion fruit juice is used to fill each bottle.

6 0
3 years ago
PLZ ANSWER THIS ITS DUE TODAY I WILL GIVE BRAINLEST!!!!
Sever21 [200]

Answer:

In many instances, the lyrics to folk songs came from existing nursery rhymes or poems, and some of the nursery rhymes had variations, depending on region or time. Thus, these folk songs may have lyrics that are slightly different from those you are familiar with.

Therefore, in my opinion, I think that Nursery songs can be considered folk music.

Im so so so so sorry if this is wrong or not the answer you were looking for. i truly am. hopefully this will be good

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
X+4 over 3 = x+6 over 4
Gnesinka [82]
If you are asking to solve for x the answer is:
x = 2
Hope This Helps!!
:)
4 0
3 years ago
Read 2 more answers
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