Answer:
0.74 N/cm
Explanation:
The following data were obtained from the question:
Mass (m) = 3 Kg
Extention (e) = 40 cm
Spring constant (K) =?
Next, we shall determine the force exerted on the spring.
This can be obtained as follow:
Mass (m) = 3 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) =?
F = mg
F = 3 × 9.8
F = 29.4 N
Finally, we shall determine the spring constant of the spring. This can be obtained as follow:
Extention (e) = 40 cm
Force (F) = 29.4 N
Spring constant (K) =?
F = Ke
29.4 = K × 40
Divide both side by 40
K = 29.4 / 40
K = 0.74 N/cm
Therefore, the spring constant of the spring is 0.74 N/cm
The answer is A. 446.9 J
Solution:
W = mgh
W = (3.8 Kg)(9.8 m/s²)(12 m)
W = 446.88 J or 446.9 J
Answer:
Stayed the same
Explanation:
Potential energy is a function of mass, gravity and height relative to a reference level. If we take as the reference level the soil, this is the level where the potential energy is zero. Since in problem it is mentioned that the track is flat, this means that there are no height changes with respect to the reference level, therefore we can say that the potential energy remains unchanged.
Ep = m*g*h
where:
m = mass [kg]
g = gravity [m/s^2]
h = elevation [m]
Answer:
Final velocity, V = 11.5m/s
Explanation:
Given the following data;
Initial velocity, U = 2.5m/s
Acceleration, a = 1.5m/s²
Time, t = 6secs
To find the final velocity, we would use the first equation of motion
V = U + at
Substituting into the equation, we have
V = 2.5 + 1.5*6
V = 2.5 + 9
Final velocity, V = 11.5m/s