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TiliK225 [7]
3 years ago
12

A distance between two consecutive troughs in a wave motion train produced in a string is 5 cm. Find speed of wave , if two comp

lete waves pass through any point per second
Physics
1 answer:
Alexxx [7]3 years ago
6 0
Speed= (frequency) x (wavelength)

= (2 per second) x (5 cm) = <em><u>10 cm/sec .</u></em>
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The world will face energy crisis in near future justify this statement
jeka57 [31]

Answer:

Nowadays most of our works are being done through different types of energy which are non-renewable. People are wasting lot of energy (hydel, dolar etc.) due to which in future we can face energy crisis.

5 0
3 years ago
A gas in a sealed container has a pressure of 50 kPa at 27°C. What will the pressure of the gas be if the temperature rises to 8
alexgriva [62]

Answer:

the final pressure of the gas is 60 kPa.

Explanation:

Given;

initial pressure of the gas, P₁ = 50 kPa = 50,000 Pa

initial temperature of the gas, T₁ = 27⁰ C = 27 + 273 = 300 k

final temperature of the gas, T₂ = 87⁰ C = 87 + 273 = 360 K

Let the final pressure of the gas = P₂

Apply pressure law;

\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} = \frac{50,000 \times 360}{300}  = 60,000 \ Pa = 60 \ kPa

Therefore, the final pressure of the gas is 60 kPa.

4 0
3 years ago
A block is released from rest, at a height h, and allowed to slide down an inclined plane. There is friction on the plane. At th
GREYUIT [131]

Here the block has two work done on it

1. Work done by gravity

2. Work done by friction force

So here it start from height "h" and then again raise to height hA after compressing the spring

So work done by the gravity is given as

W_g = m_A g(h - h_A)

Now work done by the friction force is to be calculated by finding total path length because friction force is a non conservative force and its work depends on total path

W_f = -(\mu m_A g cos\theta)(\frac{h}{sin\theta} + \frac{h_A}{sin\theta})

W_f = -\mu m_A g cot\theta(h + h_A)

Total work done on it

W = m_A g(h - h_A) - \mu m_A g cot\theta(h + h_A)

So answer will be

None of these

7 0
3 years ago
Read 2 more answers
A stretched string has a mass per unit length of 4.87 g/cm and a tension of 16.7 N. A sinusoidal wave on this string has an ampl
Burka [1]

Answer:

Explanation:

Given that,

Mass per unit length is

μ = 4.87g/cm

μ=4.87g/cm × 1kg/1000g × 100cm/m

μ = 0.487kg/m

Tension

τ = 16.7N

Amplitude

A = 0.101mm

Frequency

f = 71 Hz

The wave is traveling in the negative direction

Given the wave form

y(x,t) = ym• Sin(kx + ωt)

A. Find ym?

ym is the amplitude of the waveform and it is given as

ym = A = 0.101mm

ym = 0.101mm

B. Find k?

k is the wavenumber and it can be determined using

k = 2π / λ

Then, we need to calculate the wavelength λ using

V = fλ

Then, λ = V/f

We have the frequency but we don't have the velocity, then we need to calculate the velocity using

v = √(τ/μ)

v = √(16.7/0.487)

v = 34.29

v = 5.86 m/s

Then, we can know the wavelength

λ = V/f = 5.86 / 71

λ = 0.0825 m

So, we can know the wavenumber

k = 2π/λ

k = 2π / 0.0825

k = 76.18 rad/m

C. Find ω?

This is the angular frequency and it can be determined using

ω = 2πf

ω = 2π × 71

ω = +446.11 rad/s

D. The angular frequency is positive (+) because the direction of propagation of wave is in the negative direction of x

5 0
3 years ago
what is the force between two small charged spheres that have charges 2x10(power -7)c and 3x10(power -7)c and are placed 30 cm a
Andre45 [30]
F=1/(4*pi*e0)*q1*q2/r^2
e0 ≈ 8,854187817·10^−12
F=1/(4*pi* 8,854*10^(-12))*2*10^(-7)*2*10^(-7)/(0,3)^2 H = <span> 0,003995 </span>H ~ 0,004 H






6 0
3 years ago
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