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3 years ago

12

A distance between two consecutive troughs in a wave motion train produced in a string is 5 cm. Find speed of wave , if two comp

lete waves pass through any point per second

1 answer:

Alexxx [7]3 years ago

6 0

Speed= (frequency) x (wavelength)

= (2 per second) x (5 cm) = <em><u>10 cm/sec .</u></em>

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A football is kicked vertically upward from a height of 2 feet with an initial speed of 70 feet per seconds.

posledela

All you need to do is plug in 3 for t:h=2+70(3)−16(3^2)
and the final answer is 68.

8 0

3 years ago

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Suppose mass and radius of the planet are half and twice that of earth's respectively. If acceleration due to gravity of the ear

stich3 [128]

Answer:

The acceleration due to gravity of that planet is, gₐ = 1.25 m/s²

Explanation:

Given that,

Mass of the planet, m = 1/2M

Radius of the planet, r = 2R

Where M and R is the mass and radius of the Earth respectively.

The acceleration due to gravity of Earth, g = 10 m/s²

The acceleration due to gravity of Earth is given by the relation,

g = GM/R²

Similarly, the acceleration due to gravity of that planet is

gₐ = Gm/r²

where G is the Universal gravitational constant

On substituting the values in the above equation

gₐ = G (1/2 M)/4 R²

= GM/8R²

= 1/8 ( 10 m/s²)

= 1.25 m/s²

Hence, the acceleration due to gravity of that planet is, gₐ = 1.25 m/s²

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4 years ago

Plants are producers. What is the role of plants in an ecosystem?

Lilit [14]

Answer:

(C) Plants use oxygen to make their own food

7 0

3 years ago

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A block has two strings attached to it on opposite ends. One string has a force of 5 N,

juin [17]

Unless you have a diagram to include or any other additional info, I'll assume the block is being pulled by two opposing forces along the horizontal surface.

Horizontally, the block is under the influence of

• one rope pulling in one direction with magnitude 15 N,

• the other rope pulling in the opposite direction with mag. 5 N, and

• friction, opposing the direction of the block's motion, with mag. 3 N.

It stands to reason that the block is accelerating in the direction of the larger pulling force.

(A) By Newton's second law, we have

15 N + (-5 N) + (-3 N) = <em>m</em> (1 m/s²)

where <em>m</em> is the mass of the block. Solve for <em>m</em> :

7 N = <em>m</em> (1 m/s²)

<em>m</em> = (7 N) / (1 m/s²)

<em>m</em> = 7 kg

(B) The friction force is proportional to the normal force, so that if <em>f</em> is the mag. of friction and <em>n</em> is the mag. of the normal force, then <em>f</em> = <em>µ</em> <em>n</em> where <em>µ</em> is the coefficient of friction.

The block does not bounce up and down, so its vertical forces are balanced, which means the normal force and the block's weight (mag. <em>w</em>) cancel out:

<em>n</em> + (-<em>w</em>) = 0

<em>n</em> = <em>w</em>

<em>n</em> = <em>m</em> <em>g</em>

where <em>g</em> = 9.8 m/s² is the mag. of the acceleration due to gravity.

<em>n</em> = (7 kg) (9.8 m/s²)

<em>n</em> = 68.6 N

Then

3 N = <em>µ</em> (68.6 N)

<em>µ</em> = (3 N) / (68.6 N)

<em>µ</em> ≈ 0.044

4 0

3 years ago

A 0.03 in.diameter glass tube is inserted into SAE 30 oilat 60°F. The contact angle (i.e., the angle a liquid forms in contact w

Snowcat [4.5K]

Answer:

The value of capillary rise in the tube = 0.0363 cm

Explanation:

Diameter of the glass tube = 0.03 meter

Contact angle = 22 degree

We know that the capillary rise (h) in the tube is given by the formula =

h = (2 α cos β) / (d g R )

⇒ d = density of gasoline = 749 kg / $m^{3}$

β = 22 degree

R = radius of the tube = 0.015 m

α = surface tension of gasoline = 0.0216 N / m

cos 22 = 0.927

Put all the values in the above formula we get

⇒ h = (2 × 0.0216 × 0.927) / (749 × 9.81 × 0.015)

⇒ h = 0.0363 cm

This is the value of capillary rise in the tube.

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3 years ago