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vaieri [72.5K]
3 years ago
7

For reactions occurring at STP, the conversion between moles and liters is 22.4 L = 1 mol for all gases. How many moles of sodiu

m are in a 7.25-liter container at STP?
0.213 mol

0.126 mol

3.23 mol

0.324 mol
Chemistry
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

0.324 mole of sodium

Explanation:

From the question given above, the following data were obtained:

Volume of sodium = 7.25 L

Number of mole of sodium =..?

The number of mole of sodium that occupies 7.25 L can be obtained as follow:

22.4 L = 1 mole

Therefore,

7.25 L = 7.25 L × 1 mole / 22.4 L

7.25 L = 0.324 mole

Therefore, 0.324 mole of sodium is present in the container.

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the mechanism for a chemical reaction is shown above. which of the following statements about the overall reaction and rate laws
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The rate equation of reaction is  2H2O2 → 2 H2O + O2 and the rate law for elementary step 1 is rate=k[H2O2][I−] .

The question is incomplete, the complete question is;

Step 1: H2O2 + I− → IO− + H2O

Step 2: H2O2 + IO− →H2O + O2  + I−

The mechanism for a chemical reaction is shown above. Which of the following statements about the overall reaction and rate laws of the elementary reactions is correct?

A) The chemical equation for the overall reaction is 2 H2O2+I−→ 2 H2O+O2+I− , and the rate law for elementary step 2 is rate=k[H2O2][IO−] .

B) The chemical equation for the overall reaction is H2O2+IO−→ H2O+O2+I− , and the rate law for elementary step 2 is rate=k[H2O2]2[IO−] .

C) The chemical equation for the overall reaction is 2 H2O2→2 H2O+O2 , and the rate law for elementary step 1 is rate=k[H2O2][I−] .

D) The chemical equation for the overall reaction is 2 H2O2→2 H2O+O2 , and the rate law for elementary step 1 is rate=k[H2O2]2 .

It is possible that a chemical reaction may not take place in a single reactive encounter. In that case, we can deduce the sequence of steps by which the reaction occurs. Each step is called an elementary reaction.

The overall rate law is the sum of all the elementary reactions after the intermediates have been eliminated. In this case, the specie IO− is an intermediate. Also, I− appears on both sides of the reaction equation and it has to cancel out.

The rate equation of reaction is  2H2O2 → 2H2O + O2 and the rate law for elementary step 1 is rate=k[H2O2][I−] .

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In a room full of air, the air is mainly composed of Nitrogen and Oxygen molecules (both at room temperature). Find (to two sign
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Explanation:

Expression for the v_{rms} speed is as follows.

            v_{rms} = \sqrt{\frac{3kT}{M}}

where,   v_{rms} = root mean square speed

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                    T = temperature

                    M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of v_{rms} as follows.

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                              = 524.5 m/s

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