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3 years ago

Write a net ionic equation to show how isoquinoline, c9h7n, behaves as a base in water.

1 answer:

6 0

There can be three definitions of a base: Arrhenius base, Lewis base or Bronsted-Lowry base. Isoquinoline acts specifically as a Bronsted-Lowry base, which is a proton acceptor. Also, it acts as an Arrhenius base because it produces OH- ions after the reaction. The net ionic equation is:

C₉H₇N (aq) + H₂O ---> C₉H₇NH⁺ (aq) + OH⁻ (aq)

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Explain what happens during soil depletion and also how we can help prevent this naturally without chemicals?

Aleks04 [339]

Answer: create more healthy products for the soil and animals

Explanation:

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3 years ago

Which of a following elements is always a component of an organic compound

HACTEHA [7]

There are there elements are important in organic compounds
carbon
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3 years ago

What mass of YCL3 forms when 10.0 grams of each reactant are combined?

Triss [41]

The mass of $YCl_3$ that would be formed will be 18.22 grams

<h3>Stoichiometric calculations</h3>

Let us first look at the balanced equation of the reaction:

$2Y + 3Cl_2 --- > 2YCl_3$

The mole ratio of Y to $Cl_2$ is 2:3.

Mole of 10.0 grams of Y = 10/88.9 = 0.11 moles

Mole of 10.0 grams $Cl_2$ = 10/71 = 0.14 moles

3/2 of 0.11 = 0.165. Thus, $Cl_2$ is limiting in availability.

Mole ratio of $Cl_2$ and $YCl_3$ = 3:2

Equivalent mole of $YCl_3$ = 2/3 x 0.14 = 0.093 moles.

Mass of 0.093 moles $YCl_3$ =0.093 x 195.26 = 18.22 grams

More on stoichiometric calculations can be found here: brainly.com/question/27287858

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5 0

2 years ago

Rank these transition metal ions in order of decreasing number of unpaired electrons.

lesya692 [45]

Answer: The given transition metal ions in order of decreasing number of unpaired electrons are as follows.

$Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}$

Explanation:

In atomic orbitals, the distribution of electrons of an atom is called electronic configuration.

The electronic configuration in terms of noble gases for the given elements are as follows.

Atomic number of Fe is 26.

$Fe^{3+} - [Ar] 3d^{5}$

So, there is only 1 unpaired electron present in $Fe^{3+}$ .

Atomic number of Mn is 25.

$Mn^{4+} - [Ar]3d^{3}$

So, there are only 3 unpaired electrons present in $Mn^{4+}$ .

Atomic number of V is 23.

$V^{3+} - [Ar] 3d^{2}$

So, there are only 2 unpaired electrons present in $V^{3+}$ .

Atomic number of Ni is 28.

$Ni^{2+} - [Ar] 3d^{8}$

So, there will be 2 unpaired electrons present in $Ni^{2+}$ .

Atomic number of Cu is 29.

$Cu^{+} - [Ar] 3d^{10}$

So, there is no unpaired electron present in $Cu^{+}$ .

Therefore, given transition metal ions in order of decreasing number of unpaired electrons are as follows.

$Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}$

Thus, we can conclude that given transition metal ions in order of decreasing number of unpaired electrons are as follows.

$Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}$

7 0

3 years ago

Give answer with correct number of significant figure 600*180

zubka84 [21]

Answer:

The answer to this question is; 1.08 x 10^5

Explanation:

This is the correct option because

600 x 180 = 108,000

108,000. -> move the decimal over 5 times to get a number between 1 and 10

1.08 x 10^5

7 0

3 years ago