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3 years ago

Given the graph of the function f(x) shown below, find the average rate of change of the function f(x) on the interval [5,15].

Mathematics

1 answer:

monitta3 years ago

6 0

Answer: wheres the graph

Step-by-step explanation: In order to answer this question, I need the picture of the graph please.

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Hi doe s anyone know the answer

Svetlanka [38]

Answer:

Regular Polygon:

C, E (All sides and angles are equal)

Irregular Polygon:

A, B, (Not all sides or angles are equal)

Not a Polygon

E, F (There are curves and not a closed shape)

Hope this helps! Comment if you have any questions :)

5 0

3 years ago

Read 2 more answers

The size of matrices a and b are given. Find the sizes of ab and ba whenever they are defined. (if an answer does not exist, ent

Julli [10]

We have been given two matrices a and b. A has 6 rows and 7 columns, while b has 7 rows and 8 columns.

Since we know that order matters in matrix multiplication. In order for matrix multiplication to be defined number of columns in the first matrix should be equal to the number of rows of in the second matrix.

We can see that number of columns in matrix a and number of rows in matrix b is 7.

Therefore, size of ab will be equal to number of rows of matrix a and number of columns of matrix b that is 6 by 8.

Now we will see whether ba is defined or not. We can see columns in matrix b are 8 and rows in matrix a are 6, which is not equal. So we can say that ba is not defined.

Therefore, size of ba is not defined (dne).

7 0

3 years ago

A bucket that weighs 4lband a rope of negligible weight are used todraw water from a well that is 80ftdeep. The bucket is filled

liq [111]

Answer:

Workdone = 3200 lb.ft

Step-by-step explanation:

We are told that the bucket is filled with 40 lb of water but water leaks out of a hole in the bucket at a rate of 0.2lb/s

Thus,

Weight of water at any given time (t) would be;

w(t) = 40 - 0.2t - - - - (1)

We are told the bucket is pulled up at a rate of 2ft/s.

Thus, height at time (t); y = 0 + 2t = 2t

Since y = 2t,

Then,t = y/2

Put y/2 for t in eq 1

Thus; w(y) = 40 - 0.2(y/2)

w(y) = 40 - 0.1y

Now, at y = 80 ft, we have;

w(80) = 40 - 0.1(80)

w(80) = 40 - 8 = 32 lb

Since 32 lbs are left, it means there is always water in the bucket.

Thus, work done is;

W = 80,0[∫(Total weight).dy]

W = 80,0[∫[(weight of rope) + (weight of bucket) + (weight of water)]dy]

W = 80,0[∫[0 + 4 + 40 - 0.1y]dy]

Integrating, we have;

W = [44y - y²/20] at boundary of 80 and 0

So,

W = [44(80) - 80²/20] - [0 - 0²/20]

W = 3200 lb.ft

8 0

3 years ago

What is the solution to the system of equations shown in the graph?

Katen [24]

The solution is where both lines intersect. First find the x-coordinate which we will find by going to the left two units. That means x = -2. Now going up one unit, which gives us y = 1

(-2, 1)

8 0

3 years ago

Read 2 more answers

12/15 * 5/6

nydimaria [60]

La multiplicación de las fracciones es 2/3

Para multiplicar las dos fracciones tenemos que multiplicar en línea: numerador por numerador y denominador por denominador.

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\sf \rightarrow \dfrac{12}{15} \times \dfrac{5}{6} }$