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Ilia_Sergeevich [38]
2 years ago
9

20 PTS Solve the following using synthetic division pls

Mathematics
1 answer:
ankoles [38]2 years ago
4 0

Answer:

hbvthj rg rkgn tlkeg ergtn ergkl efhtlkjer ht efkthn  dkhtn lkeghkt erthkl gngkh  htlkn ht

Step-by-step explanation:

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What is the weight per cm? ​
Dmitry [639]

Answer:

  2/5 g/cm

Step-by-step explanation:

When you want to know "A per B", divide the given quantity of A by the corresponding quantity of B. ("Per" essentially means "divided by".)

It can be convenient to choose table values that make the division easy:

  12 g/(30 cm) = 4/10 g/cm = 0.4 g/cm

  20 g/(50 cm) = 2/5 g/cm . . . . . . . . . . . . . same as 0.4 g/cm

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Step-by-step explanation:

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2 years ago
In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

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Answer:

75%

Step-by-step explanation:

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