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myrzilka [38]
3 years ago
15

James is playing his favorite game at the arcade. After playing the game 33 times, he has 88 tokens remaining. He initially had

2020 tokens, and the game costs the same number of tokens each time. The number t of tokens James has is a function of g, the number of games he plays. Write the function's formula. t=t
Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Answer:

t = 64g

Step-by-step explanation:

This is quite straightforward

Let n be the number of tokens he is charged per game.

88 = 2200 - 33n

33n = 2200 - 88

33n = 2112

n = 2112/33 = 64

Now, we write the relation. The number of tokens t at any point in time is 64 multiplied by the number of games

t = 64g

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Solve the system of equations by finding the reduced row echelon form of the augmented matrix. Write the solutions for x and y i
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The solutions for the given system of equations are:

\left \{ {{x=-5} \atop {y=12-4z}} \right.

Step-by-step explanation:

Given the equation system:

\left \{ {{3x+y+4z=-3} \atop {-x+y+4z=17}} \right.

We obtain the following matrix:

\left[\begin{array}{cccc}3&1&4&-3\\-1&1&4&17\end{array}\right]

<u>Step 1:</u> Multiply the fisrt row by 1/3.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\-1&1&4&17\end{array}\right]

<u>Step 2:</u> Sum the first row and the second row.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&\frac{4}{3} &\frac{16}{3}&16\end{array}\right]

<u>Step 3:</u> Multiply the second row by 3/4.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&1 &4&12\end{array}\right]

<u>Step 4:</u> Multiply the second row by -1/3 and sum the the first row.

\left[\begin{array}{cccc}1&0 &0&-5\\0&1 &4&12\end{array}\right]

The result of the reduced matrix is:

\left \{ {{x=-5} \atop {y+4z=12}} \right.

This is equal to:

\left \{ {{x=-5} \atop {y=12-4z}} \right.

These are the solutions for the system of equations in terms of z, where z can be any number.

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