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iragen [17]
3 years ago
7

A Write an explicit formula for an, the nth term of the sequence 17, 15, 13, ...

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0

Tn=-2n+19

Step-by-step explanation:

Well in south africa we use Tn

Tn=a+(n-1)d

a=is the first term in the sequence which is 17

d=is the the difference between the terms which is - 2

Tn=17+(n-1)(-2)

Tn=17-2n+2

Tn=-2n+19

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John sent 1,302 text messages in 6 weeks, How many texts was he sending per week (At what rate was he sending texts per week)?​
Llana [10]

Answer:

217 text messages

Step-by-step explanation:

1302/6 = 217

3 0
2 years ago
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What equation represents the model shown below?
g100num [7]

Given:

The algebra tiles of an equation.

To find:

The equation represented by the given model.

Solution:

On the left side of the model we have 4 tiles of (-x) and 3 tiles of (-1). So,

LHS=(-x)+(-x)+(-x)+(-x)+(-1)+(-1)+(-1)

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On the right side of the model we have 8 tiles of (-1). So,

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Now, equate the LHS and RHS to get the equation.

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7 0
3 years ago
Find the value of x. Show your work.<br><br> WILL GIVE BRAINLIEST!!!!!
sergeinik [125]
The answer is 54
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3 0
3 years ago
Further mathematics: Find the derivative of the function x^2 y + (xy)^3 +3x=0 at (-1 , 3)​
vesna_86 [32]

Answer:

3.

Step-by-step explanation:

Implicit differentiation:

x^2 y + (xy)^3 + 3x = 0

x^2 y + x^3y^3 + 3x = 0

Using the product rule:

2x* y + x^2*dy/dx + 3x^2 y^3 + x^3* (d(y^3)/dx) + 3 = 0

2xy + x^2 dy/dx + 3x^2 y^3 + x^3* 3y^2 dy/dx + 3 = 0

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dy/dx=  (-2xy - 3x^2y^3 - 3) / (x^2 + 3y^2x^3)

At the point (-1, 3).

the derivative =  (6 - 81 - 3)/(1 -27)

= -78/-26

=  3.

8 0
2 years ago
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Sedaia [141]
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