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iragen [17]
3 years ago
7

A Write an explicit formula for an, the nth term of the sequence 17, 15, 13, ...

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0

Tn=-2n+19

Step-by-step explanation:

Well in south africa we use Tn

Tn=a+(n-1)d

a=is the first term in the sequence which is 17

d=is the the difference between the terms which is - 2

Tn=17+(n-1)(-2)

Tn=17-2n+2

Tn=-2n+19

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Evaluate the expression for the given variable <br>-4p+1 when p=2​
Rama09 [41]
-4p+1 = -4(2)+1 = -8+1 = -7
8 0
2 years ago
Can you please help me with this
UNO [17]
Parentheses. Exponents. Multiplication Division. Addition Subtraction.

2) 6 x (11 - 5)- 7^2
6 x (6) - 7^2
6 x 6 - 49
36 - 49
-13

3) (40 - 2^2) / (-4 + 6)
(40 - 4) / (-4 + 6)
(36) / (2)
36/2
13/1
13

4) (66 - 6) / 6 - 2^2
(60) / 6 - 2^2
60 / 6 - 4
60 / 2
30 / 1
30
4 0
3 years ago
If k-9=5(k-3)find k​
jok3333 [9.3K]

Answer:

K = 3/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

k−9=5(k−3)

k+−9=(5)(k)+(5)(−3)(Distribute)

k+−9=5k+−15

k−9=5k−15

Step 2: Subtract 5k from both sides.

k−9−5k=5k−15−5k

−4k−9=−15

Step 3: Add 9 to both sides.

−4k−9+9=−15+9

−4k=−6

Step 4: Divide both sides by -4.

-4k/-4 = -6/-4

K = 3/2

7 0
3 years ago
Read 2 more answers
If f(x)=3x^3 then what is the area enclosed by the graph of the function, the horizontal axis, and vertical lines at x=2 and x=4
Ber [7]

Answer:

Area: 180 units2 (units 2 is because since the are no specific unit given but every area should have a unit  of measurement)

Step-by-step explanation:

The area enclosed by the graph of the function, the horizontal axis, and vertical lines is the integral of the function between thos two points (x=2 and x=4)

So , let's solve the integral of f(x)

Area =\int\limits^2_4 3{x}^3 \, dx = 3*x^4/4+C

C=0

So if we evaluate this function in the given segment:

Area= 3* (4^4)/4-3*(2^4)/4= 3*(4^4-2^4)/4=180 units 2

Goos luck!

5 0
3 years ago
6 Paul runs 1.5 km on the bearing 127°. a Draw a diagram of the situation. b How far east is Paul from his starting point? ( How
GenaCL600 [577]

By running in a bearing of 127°, Paul motion is in the south eastern direction.

Correct responses:

a. Please find attached the required diagram created with MS Visio

b. Paul's distance travelled east is approximately 11.98 km

  • Paul's distance travelled south is approximately 0.903 km

<h3>Method used for diagram and for the distance calculation</h3>

Given:

The distance Paul runs = 1.5 km

The bearing Paul is running = 127°

a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction

Please find attached the diagram representing the situation, created with MS Visio.

b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;

  • Paul's distance east =  15 km × cos(37°) ≈ <u>11.98 km</u>

Pau's distance travelled in the south direction relative to the starting point

is given by the vertical distance travelled relative to the x-axis, which is

given as follows;

Distance Paul travels south = 1.5 km × sin(37°) ≈ <u>0.903 km</u>

Learn more about bearings in trigonometry here:

brainly.com/question/23427938

5 0
2 years ago
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