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2 years ago

Find the slope between the points. �. (5, −3) (7, 4)

Mathematics

2 answers:

aliya0001 [1]2 years ago

8 0

Answer:

$\boxed {\boxed {\sf m= \frac{7}{2} \ or \ 3.5 }}$

Step-by-step explanation:

The slope formula is the change in y over the change in x.

$m=\frac{y_2-y_1}{x_2-x_1}$

In this formula, (x₁, y₁) and (x₂, y₂) are the points given. We are given the points (5, -3) and (7,4). Therefore,

$x_1=5 \\y_1= -3\\x_2=7 \\y_2=4$

Substitute the values into the formula.

$m=\frac{4--3}{7-5}$

Solve the numerator.

4 - -3 = 4+3 = 7

$m=\frac{7}{7-5}$

Solve the denominator

7-5=2

$m=\frac{7}{2}$

$m=3.5$

The slope between the points is 7/2 or 3.5

Gelneren [198K]2 years ago

6 0

Answer: slope is $\frac{7}{2}$ or 3.5

Step-by-step explanation:

Slope = $\frac{y_2-y_1}{x_2-x_1}$ = $\frac{4-(-3)}{7-5}$ = $\frac{7}{2}$

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Ms. Carey grades 4 tests during her lunch. She grades 1/3 of the remainder after school. If she syill5has 16 test to grade after

enot [183]

Answer: 24 tests

Step-by-step explanation:

Ms. Carey graded 1/3 of the tests and still had 16 tests to go.

This means that the 16 tests represent the remaining proportion of the total number of tests:

= 1 - 1/3

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What is the equation of the following line written in slope-intercept form -2/3 and -1/-4? y = -11x - 7 y = -7x + 11 y = -7x - 1

Snowcat [4.5K]

Answer:

$y=-7x-11$

Step-by-step explanation:

Given:

The two points on the line are $(-2,3)$ and $(-1,-4)$ .

The slope of the line joining two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

$Slope,m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here, $x_{1}=-2,y_{1}=3,x_{2}=-1,y_{2}=-4$

∴ $m=\frac{-3-4}{-1-(-2)}=\frac{-7}{-1+2}=\frac{-7}{1}=-7$

Equation of line with a point $(x_{1},y_{1})$ and slope $m$ is given as:

$y-y_{1}=m(x-x_{1})$

Plug in -2 for $x_{1}$ , 3 for $y_{1}$ and -7 for $m$ . This gives,

$y-3=-7(x-(-2))\\y-3=-7(x+2)\\y-3=-7x-(7\times 2)\\y-3=-7x-14\\y=-7x-14+3\\y=-7x-11$

Therefore, the equation of the line in vertex form is $y=-7x-11$ .

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2 years ago

The volume of the triangular prism is 54 cubic units.What is the value of x?

nadezda [96]

Answer:

x=3

Step-by-step explanation:

the volume of the prism with triangular base is 54 unit³

The base is a triangle with, base i.e 4 units and height i.e x units

Also, height of the prism = 3x

So, volume of the prism is,

And

$Area_{Triangle}=\dfrac{1}{2}\times base\times Height_{Triangle}=\dfrac{1}{2}\times 4\times x=2x\ unit^2$

Then,

$V_{Prism}=2x\times 3x=6x^2$

As the volume is given as 54 unit³, hence

6x²=54

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Aleonysh [2.5K]

Answer:

Step-by-step explanation:

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