1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kobusy [5.1K]
3 years ago
11

152 2s22p6 3s2 3pó 452 3d5

Chemistry
1 answer:
damaskus [11]3 years ago
3 0

Answer:

Sorry I didn't understand your question

You might be interested in
If you are running at top speed and try to stop suddenly, what happens?
vlada-n [284]

You are going to fall, face first on the ground.

7 0
2 years ago
Paano mag ka jowa? any suggestions?​
melamori03 [73]

Well just wait for the right time to come, Because if you wait for the right time, you're gonna find someone who you really want- I'm bad at understanding tagalog

6 0
3 years ago
Read 2 more answers
Which of the following pairs of elements could possibly be in the same group? X has a 1+ ion; Y has a 1- ion. X tends to form a
exis [7]
Let's eliminate these one by one.
The first pair would not be the same, as X would most likely be in group IA, and Y would be in group VIIA, because of their tendency to gain and lose electrons.
The second pair would also violate the same rule, but X would most likely be in group IIA, and Y would most likely be in group VIA.
The third pair would not be the same, as X is most likely in group VIIA, and since Y has eight valence electrons, it is most likely a noble gas.
The final pair has X with atomic number 15, making it phosphorous. Phosphorous wants to gain 3 electrons to have a full octet of 8 outer "valence" electrons, and Y would also like to gain 3 electrons. This means it is possible that the final pair would be in the same group.
5 0
4 years ago
Read 2 more answers
A copper cylinder, 12.0 cm in radius, is 44.0 cm long. If the density of commoner is 8.90 g/cm3, calculate the mass in grams of
inna [77]

The mass of the copper cylinder is 177065.856g

Given:

Radius of the copper cylinder R=12cm

Height of the copper cylinder H=44cm

Density of the cylinder=8.90 \frac{g}{c m^{3}}

To find:

Mass of the copper cylinder

<u>Step by Step by explanation:</u>

Solution:

According to the formula, Mass can be calculated as

\rho=\frac{m}{v} and from this

m=\rho \times v

Where, m=mass of the cylinder

\rho =density of the cylinder

v=volume of the cylinder

And also cylinder is provided with radius and height value.

So volume of the cylinder is calculated as

v=\pi r^{2} h

Where \pi=3.14

r=radius of the cylinder=12cm

h=height of the cylinder=44cm

Thus, v=3.14 \times 12^{2} \times 44

v=3.14 \times 144 \times 44

v=19895.04 \mathrm{cm}^{3}

And we know that, m=\rho \times v

Substitute the known values in the above equation we get

m=8.90 \times 19895.04  

m=177065.856g or 177.065kg

Result:

Thus the mass of the copper cylinder is 177065.856g

4 0
4 years ago
The _________________ are either elements or compounds which are present prior to a chemical reaction.
mr Goodwill [35]
Reactants would be the missing word in the sentence because they make up the products in a chemical reaction
3 0
3 years ago
Read 2 more answers
Other questions:
  • How many moles are in 2.0 grams of FeO
    14·2 answers
  • For each of the following unbalanced reactions, sup- pose exactly 5.00 g of each reactant is taken. Deter- mine which reactant i
    15·1 answer
  • PLEASE HELP!!! I am taking a college chem class as a junior and have no idea how to do this!
    10·1 answer
  • Fill in the coefficients that will balance the following reaction: a0PbI4 + a1CrCl3 → a2PbCl4 + a3CrI3
    10·2 answers
  • How do I solve this?? ok having a hard time BRAINLIST​
    10·1 answer
  • Control variables are parts of the experiment that you try to:
    11·2 answers
  • Describe the energy transformation when a match burns.
    6·1 answer
  • Draw the product(s) obtained when benzoquinone is treated with excess butadiene. using wedges and dashes, indicate the stereoche
    14·1 answer
  • Imagine an alternate universe where the value of the Planck constant is 6.6207 x 10^-36 J*s.
    8·1 answer
  • Question 6 of 25
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!