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pshichka [43]
3 years ago
14

Which substance is a gas at room temperature and atmospheric pressure?

Chemistry
1 answer:
natulia [17]3 years ago
8 0
Ar is a substance that is a gas at room temperature and atmospheric pressure.
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Calculate the concentration in % (m/m) of a solution containing 30.0g of mgcl2 dissolved in 270.0g of h20
qaws [65]
As the question tells you, you need to use the formula

% mass= mass of solute/ mass of solution x 100

mass solute= 30.0 g
mass of solution= 30.0 + 270.0= 300.0 g

% mass= 30.0/ 300.0 x 100= 10%

answer is B
4 0
3 years ago
The pictures to the right, show two different models of the atom. Type in the letter of your answer. Which model best represents
Solnce55 [7]

Answer:

Model B

Explanation:

Just did it on Edgenuity.

6 0
3 years ago
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Which of the following statements is true?
AlekseyPX

Answer:

C

Explanation:

Its eurasian plate.

8 0
3 years ago
An emerald gemstone is an impure form of the mineral beryl, Be3Al2Si16O18. What is the percentage of silicon in the mineral?
solong [7]

Answer:

b. 54.9%

Explanation:

An emerald gemstone has the formula Be₃Al₂Si₁₆O₁₈. We can find the mass of each element in 1 mole of Be₃Al₂Si₁₆O₁₈ by multiplying the molar mass of the element by its atomicity.

Be: 3 × 9.01 g = 27.03 g

Al: 2 × 26.98 g = 53.96 g

Si: 16 × 28.09 g = 449.4 g

O: 18 × 16.00 g = 288.0 g

Total mass = 818.4 g

The mass percentage of silicon is:

(449.4 g / 818.4 g) × 100% = 54.91%

4 0
3 years ago
If a gas is 16 times as heavy as hydrogen which will diffuse faster and by what ratio​
vodka [1.7K]

Answer:

1. Hydrogen will diffuse faster.

2. The ratio of diffusion of hydrogen gas to that of the unknown gas is 4 : 1

Explanation:

Let the rate of diffusion of hydrogen gas, H2 be R1

Let the molar mass of H2 be M1

Let the rate of diffusion of the unknown gas be R2.

Let the molar mass of the unknown gas be M2.

Molar mass of H2 (M1) = 2x1 =2g/mol

Molar mass of unknown gas (M2) = 16 times that of H2

= 16 x 2 = 32g/mol

1. Determination of the gas that will diffuse faster. This is illustrated below:

R1/R2 = √(M2/M1)

R1/R2 = √(32/2)

R1/R2 = √16

R1/R2 = 4

Cross multiply

R1 = 4R2

From the above calculations, we can see that the rate of diffusion H2 (R1) is four times the rate of diffusion of the unknown gas (R2).

Therefore, hydrogen will diffuse faster.

2. Again, from the calculations made above, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is given by;

R1/R2 = 4

Therefore, the ratio of diffusion of hydrogen (R1) to that of the unknown gas (R2) is:

4 : 1

7 0
3 years ago
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