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patriot [66]
3 years ago
10

Solve this equation. Please show work. log(4m-10)=1

Mathematics
1 answer:
Ede4ka [16]3 years ago
5 0

Answer:

m=5

Step-by-step explanation:

1. Convert the logarithm into exponential form using the fact that log_{a}(x)=b is equal to x=a^{b} so ... 4m-10=10^{1}

2. Any expression raised to the power of 1 equals itself so ... 4m-10=10

3. Move the constant to the right-hand side and change its sign so ... 4m=10+10

4. Add the numbers so ... 4m=20

5. Divide both sides of the equation by 4 so ... m=5, m>\frac{5}{2}

6. Check if the solution is in the defined range so ... m=5

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Let a=\tan A and b=\sin A. Then

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and

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\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

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4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A

so that

m^2-n^2=4\sqrt{mn}

as required.

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