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alexandr402 [8]
3 years ago
5

HELP 15-21 PLEASE!!!

Chemistry
2 answers:
suter [353]3 years ago
7 0

Answer:

ANSWER

Explanation:

Harlamova29_29 [7]3 years ago
6 0

Answer:

15. Lead (II) chloride

16. potassium chloride

17. Lithium oxide

18. Arsenious trioxide

19.Phosphorus tribromide

Explanation:

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A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What
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Answer:

The answer to your question:  0.7 M

Explanation:

Data

V of KOH = 90 ml

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V H2SO4 = 21.2 ml

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                       2KOH(aq)  +  H₂SO₄(aq)   →   K₂SO₄(aq)  +  2H₂O(l)

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                    2 moles of KOH --------------  1 mol of H₂SO₄

                   x                           --------------  31.8 mol of H₂SO₄

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