All categories

3 years ago

How many liters of nitrogen gas is produced if 50.0L of water is produced at STP?

Chemistry

1 answer:

Alona [7]3 years ago

8 0

Answer:

25.0 liter of nitrogen gas

Explanation:

1. Chemical equation

Ammonium nitrite is a solid compound that decomposes into nitrogen gas and water vapor as per this chemical equation:

$NH_4NO_2(s)\rightarrow N_2(g)+2H_2O(g)$

2. Mole ratio

$1molN_2(g)/2molH_2O(g)$

3. Volume ratio

Since, both species are gases and are at same temperature and pressure, the volume ratio is equal to the mol ratio.

Thus, the volume ratio is:

$1literN_2(g)/2literH_2O(g)$

4. Use the volume ratio with the known amount of water produced

$50.0literH_2O(g)\times 1literN_2(g)/2literH_2O(g)=25.0literN_2(g)$

You might be interested in

A person loses 2.70 lb in two weeks. how many grams did they lose?

leonid [27]

Answer:

1224.7

Explanation:

Each lb is 453.59

6 0

3 years ago

Some distilled water is added to an empty beaker. a gram of copper (ii) nitrate is added to the beaker and while the water is be

Xelga [282]

Copper ions, nitrate ions, and water is in the beaker

6 0

3 years ago

Backpackers often use canisters of white gas to fuel a cooking stove’s burner. If one canister contains 1.45 L of white gas, and

rusak2 [61]

1 L ------- 1000 cm³
1.45 L ----- ???

1.45 * 1000 = 1450 cm³ ( volume )

Density = 0.710 g/cm³

mass = in Kg

m = D * V

m = 0.710 * 1450

m = 1029.5 g

1 Kg ------- 1000 g
kg -------- 1029.5 g

mass = 1029.5 / 1000

mass = 1.0295 Kg

hope this helps!

7 0

3 years ago

The characteristic flame test colors of metal ions are due to atomic emission spectra. Duscuss the relationship between the abso

vesna_86 [32]

The characteristics flame test color of metal ions are because of the atomic emission spectra.

When an atom absorbs a particular wavelength radiation, the electrons within it, move from lower energy level to the higher level of energy. Such a procedure is called absorption. When this stimulated electron to come back to its ground state, it loses energy in particular color on the basis of the frequency of the absorbed radiation. Such a procedure is called emission.

As an atom exhibit, distinct levels of energy, the level close to the nucleus possess less energy in comparison to the level, which is far from the nucleus. So, electrons move from lower energy level to the higher level by attaining particular energy, and after excitation, it comes back from high energy level to a low energy level with the emission of light.

According to Planck's concept, there is a specific difference of energy between the two energy level, so such energy difference is quantized. Only those radiation are absorbed, which are equivalent to the difference of energy between the two levels.

8 0

3 years ago

Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o

vivado [14]

Answer:

For 1: The amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

For 2: The amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

Explanation:

For 1:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Molarity of $KIO_3$ solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

$0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol$

Hence, the amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

For 2:

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

$2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3$

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = $\frac{1}{2}\times 0.00025=0.000125mol$ of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

6 0

3 years ago