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IgorLugansk [536]
3 years ago
9

List two properties of mixtures

Chemistry
1 answer:
Volgvan3 years ago
3 0
Composition, and a c<span>hemical reaction.</span>
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What are the effects of inhalation of acetone vapor?
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it can cause irritation in eyes throat and lungs and u can become lightheaded, or possibly fall in a coma

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Explain why either liquids nor gases have permanent shapes
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Because they can't get trapped in.
5 0
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I need help with this plz help
schepotkina [342]

Answer:

\rm ^{103}_{\phantom{1}40}Zr, zirconium-103.

Explanation:

In a nuclear reaction, both the mass number and atomic number will conserve.

Let ^{A}_{Z}\mathrm{X} represent the unknown particle.

The mass number of a particle is the number on the upper-left corner. The atomic number of a particle is the number on its lower-left corner under the mass number. For example, for the particle ^{A}_{Z}\mathrm{X}, A is the mass number while Z while Z is the atomic number.

Sum of mass numbers on the left-hand side of the equation:

\underbrace{239}_{^{239}_{\phantom{2}94}\mathrm{Pu}} + \underbrace{1}_{^{1}_{0}\mathrm{n}} = 240.

Note that there are three neutrons on the right-hand side of the equation. Sum of mass numbers on the right-hand side:

\underbrace{A}_{^{A}_{Z}\mathrm{X}} + \underbrace{134}_{^{134}_{\phantom{2}54}\mathrm{Xe}} + \underbrace{3\times 1}_{3\;^{1}_{0}\mathrm{n}} = A + 137.

Mass number conserves. As a result,

A + 137 = 240.

Solve this equation for A:

A = 103.

Among the five choices, the only particle with a mass number of 103 is \rm ^{103}_{\phantom{1}40}Zr. Make sure that atomic number also conserves.

3 0
3 years ago
An unknown amount of Al203 decomposed producing 215 g of solid aluminum. 2Al2O3=4Al+3O2 How many grams of oxygen gas should be p
natulia [17]

Answer:

191.11 grams of oxygen gas should be produced.

Explanation:

The balanced reaction is:

2 Al₂O₃ → 4 Al + 3 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Al₂O₃: 2 moles
  • Al: 4 moles
  • O₂: 3 moles

Being the molar mass of each compound:

  • Al₂O₃: 102 g/mole
  • Al: 27 g/mole
  • O₂: 32 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Al₂O₃: 2 moles* 102 g/mole= 204 grams
  • Al: 4 moles* 27 g/mole= 108 grams
  • O₂: 3 moles* 32 g/mole= 96 grams

Then you can apply the following rule of three: if by stoichiometry 108 grams of aluminum are produced along with 96 grams of oxygen, 215 grams of aluminum are produced along with how much mass of oxygen?

mass of oxygen=\frac{215 grams of aluminum*96 grams of oxygen}{108grams of aluminum}

mass of oxygen= 191.11 grams

<u><em>191.11 grams of oxygen gas should be produced.</em></u>

6 0
3 years ago
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