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3 years ago

Write a balanced equation for the following reaction;

Chemistry

1 answer:

Kazeer [188]3 years ago

3 0

Answer:

6K + N₂ —> 2K₃N

Explanation:

K + N₂ —> K₃N

The above equation can be balanced as illustrated below:

K + N₂ —> K₃N

There are 2 atoms of N on the left side and 1 atom on the right side. It can be balance by putting 2 in front of K₃N as shown below:

K + N₂ —> 2K₃N

There are 6 atoms of K on the right side and 1 atom on the left side. It can be balance by putting 6 in front of K as shown below:

6K + N₂ —> 2K₃N

Now the equation is balanced.

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In the original mixtures, test tube 1 contained magnesium and a zinc compound, and test tube 2 contained zinc

FromTheMoon [43]

Answer:

Test tube one is a compound because it is 2 elements combine..Test tube to is an element

Explanation:

5 0

3 years ago

I need help on thiss

Sergio039 [100]

The reaction is not balanced

<h3>Further explanation</h3>

Given

Reaction

2Fe(s)+3O₂(g)⇒2Fe₂O₃(s)

Required

The number of atoms

Solution

In a balanced chemical equation, the number of atoms in the compound that reacts (the reactants and products) will have the same number

Reactants : Fe(s)+O₂(g)

Fe = 2 atoms

O = 3 x 2 = 6 atoms

Products : Fe₂O₃(s)

Fe = 2 x 2 = 4 atoms

O = 2 x 3 = 6 atoms

The reaction is not balanced because the number of Fe atoms is not the same

The balanced reaction should be:

4Fe(s)+3O₂(g)⇒2Fe₂O₃(s)

8 0

3 years ago

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valkas [14]

Answer:

Explanation:

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7 0

3 years ago

Read 2 more answers

15.1 L N2 at 25 °C and 125 kPa and 44.3 L O2 at 25 °C and 125 kPa were transferred to a tank with a volume of 6.25 L. What is th

Y_Kistochka [10]

Answer:

The total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.

Explanation:

For N2,

Pressure(P₁)=125 kPa

Volume(V₁)=15·1 L

Temperature (T₁)=25°C=25+273 K=298 K

Similarly, for Oxygen,

Pressure(P₂)= 125 kPa

Volume(V₂)= 44.3 L

Temperature(T₂)=25°C= 298 K

Then, for the mixture,

Volumeof the mixture( V)= 6.25 L

Pressure(P)=?

Temperature (T)= 51°C = 51+273 K=324 K

Then, By Combined gas laws,

$\frac{P_{1} V_{1} }{T_{1} } +\frac{P_{2} V_{2} }{T_{2} } =\frac{PV}{T}$

or, $\frac{15.1*125}{298} +\frac{44.3*125}{298} =\frac{P*6.25}{324}$

or, $6.34+18.58=\frac{P*6.25}{324}$

or, $P=\frac{24.92*324}{6.25}$

∴P=1291.85 kPa

So the total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.

3 0

3 years ago

Measurements include

Keith_Richards [23]

There’s lots of measurements. (m, kg, s, mol, cm, in, mm) etc

8 0

4 years ago