Answer: 
Step-by-step explanation:
The area of a rectangle can be calculated with the formula:

l: the length of the rectangle.
w: the width of the rectangle.
The area of the remaning wall after the mural has been painted, will be the difference of the area of the wall and the area of the mural.
Knowing that the dimensions of the wall are
by
, its area is:

As they are planning that the dimensions of the mural be
by
, its area is:

Then the area of the remaining wall after the mural has been painted is:

Answer:
- Option <u>B </u>is correct i.e. <u>2</u><u>1</u>
Step-by-step explanation:
In the question we're provided with an equation that is :
And we are asked to find the solution for the equation .
<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>
<u>
</u>
Multiplying by 7 on both sides :

On further calculations , we get :

- <u>Therefore</u><u> </u><u>,</u><u> </u><u>solution</u><u> </u><u>for</u><u> equation</u><u> </u><u>is </u><u>2</u><u>1</u><u> </u><u>.</u><u>That </u><u>means</u><u> </u><u>option </u><u>B </u><u>is </u><u>the </u><u>correct</u><u> answer</u><u>.</u>
<u>Verifying</u><u> </u><u>:</u>
We are verifying our answer by substituting value of v in the equation given in question :

Putting value of v :

By dividing 21 with 7 , we get :



- <u>Therefore</u><u> </u><u>,</u><u> </u><u>our </u><u>answer</u><u> is</u><u> valid</u><u> </u><u>.</u>
<h2>
<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
The distance between the two points on the number line is of
units.
-------------------------------------------
- The distance between two numbers on the number line is given by the <u>subtraction of the greater by the smaller number.</u>
- The greater number is

- The smaller is
. - The distance is:

Thus, distance of
units.
A similar problem is given at brainly.com/question/10795861
2 and 14/15
Because the first step of subtraction is common denominators
Answer:
DGH has a different number than Ce and FI