Answer:
x = 26.45
Step-by-step explanation:
Cos theta = adjacent side / hypotenuse
cos 50 = 17 /x
Switch the x and the cos 50
x = 17 / cos 50
x =26.44730506
Rounding to 2 decimal places
x = 26.45
Answer:
Height of the square pyramid is 6.569 centimeter
Step-by-step explanation:
The volume of the square pyramid is 94.5 cubic centimeters
The height of the square pyramid will be equal to the lengths of the sides of the square.
The volume of the square pyramid is given by
or
![\frac{a^3}{3} = 94.5\\a^3 = 94.5 *3\\a = \sqrt[3]{94.5*3} \\a = 6.569](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E3%7D%7B3%7D%20%20%3D%2094.5%5C%5Ca%5E3%20%3D%2094.5%20%2A3%5C%5Ca%20%3D%20%5Csqrt%5B3%5D%7B94.5%2A3%7D%20%5C%5Ca%20%3D%206.569)
centimeter
Height of the square pyramid is 6.569 centimeter
Answer:
Jon lost a total of 3 kilograms in these 3 months.
Step-by-step explanation:
Weight that Jon gained in December = 2.2 kilograms
Weight that Jon lost in January = 1.5 kilograms
Weight that Jon lost in February = 3.7 kilograms
Overall Change in his weight = Total Weight he gained - Total weight he Lost
Total weight he gained is 2.2 kilograms as he only gained weight in December. Total weight he lost will be sum of weights he lost in January and February.
So, total weight Jon lost = 1.5 + 3.7 = 5.2 kilograms
Thus,
Total change in Jon's Weight = 2.2 - 5.2 = -3.0 kilograms
This shows that Jon lost a total of 3 kilograms in these 3 months.
Conclusion:
The statement that best describe the total change in his weight is: Jon lost a total of 3 kilograms in these 3 months
Check the picture below.
so, the center of the circle is the midpoint of that diametrical segment, and half that length is the radius.
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ -2 &,& -4~) % (c,d) &&(~ 3 &,& 8~) \end{array}~~~ % distance value d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[3-(-2)]^2+[8-(-4)]^2}\implies d=\sqrt{(3+2)^2+(8+4)^2} \\\\\\ d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13\qquad\qquad \qquad \stackrel{radius}{\frac{13}{2}}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%0A%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%26%26x_2%26%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%26%28~%20-2%20%26%2C%26%20-4~%29%20%0A%25%20%20%28c%2Cd%29%0A%26%26%28~%203%20%26%2C%26%208~%29%0A%5Cend%7Barray%7D~~~%20%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%3D%5Csqrt%7B%5B3-%28-2%29%5D%5E2%2B%5B8-%28-4%29%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%283%2B2%29%5E2%2B%288%2B4%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%3D%5Csqrt%7B25%2B144%7D%5Cimplies%20d%3D%5Csqrt%7B169%7D%5Cimplies%20d%3D13%5Cqquad%5Cqquad%20%5Cqquad%20%20%5Cstackrel%7Bradius%7D%7B%5Cfrac%7B13%7D%7B2%7D%7D)
Answer:
D. enlargement
Step-by-step explanation:
enlargement means to increase something
