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3 years ago

Pls help me with this one!! :>

Mathematics

2 answers:

Colt1911 [192]3 years ago

3 0

Answer:

i dont see a picture?

Step-by-step explanation:

Elza [17]3 years ago

3 0

Step-by-step explanation:

the student who has the highest grades in a particular group of students and who gives the valedictory speech at a graduation ceremony compare salutatorian.

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To dived 572÷4, Stanley estimated to place the first digit of the quotient. In which place is the first digit of the question?

Helga [31]

Answer:

Step-by-step explanation:

i am not do sure but i think its in the ones place...

-sorry if im wrong

5 0

3 years ago

A quadratic function is defined by \small f\left(x\right)=x^2-8x-4. Which expression also defines \small f and best reveals the

ohaa [14]

Answer:

f(x) = [x – (4 + √20)][x – (4 – √20]

Step-by-step explanation:

In order to know the function that best describes the given f(x) that best reveals it's minimum or maximum, we need to know solve for x.

x² – 8x – 4 = 0

Using completing the square method

x² – 8x = 4

x² – 8x + 4² = 4 + 4²

(x – 4)² = 20

x = 4 ±√20

Therefore

f(x) = [x – (4 + √20)][x – (4 – √20]

6 0

3 years ago

Twins James and Jamie are getting bunk beds.their parents picked up the box from ruthand found that has dimensions of 6' x 2' x

Oksana_A [137]

The box with the bunk bed will not fit in the mini van

Step-by-step explanation:

Step 1 :

Given

Length of the cuboid = 6 feet

Width of the cuboid = 2 feet

Height of the cuboid = 3 feet

The diagonal of the cuboid is

$\sqrt{l^{2}+w^{2}+h^{2}} = \sqrt{6^{2}+2^{2}+3^{2}}\\= \sqrt{49}$

= 7 feet

Step 2 :

The utmost length of the diagonal of the box which the minivan can hold is 6.8 feet

The length of the diagonal of the box containing the bunk bed is 7 feet which is greater than 6.8 feet.

Hence the trunk of the mini van cannot hold the bunk bed

5 0

3 years ago

Hey Mahfia, please help! Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at

Dafna1 [17]

Answer:

$\huge\boxed{ \red{ \boxed{ \tt{ \frac{ {y}^{2} }{ {10}^{2} } - \frac{ {x}^{2} }{ {12}^{2} } = 1}}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

conic sections
PEMDAS

<h3>tips and formulas:</h3>

$\sf hyperbola \:equation : \\ \sf \frac{ {x}^{2} }{ {a}^{2} } - \frac{ {y}^{2} }{ {b}^{2} } = 1$
vertices of hyperbola:(±a,0) and (0,±b) if reversed
$\sf \: asymptotes : \\ y = \pm\frac{b}{a} x$