2/3 of a number is greater than 66% of a number
Try multiplaying all sides
Answer:
D:) (2,2,) is the Answer
Step-by-step explanation:
Solve the following system:
{X - 2 Y = -2 | (equation 1)
{3 X - 2 Y = 2 | (equation 2)
Swap equation 1 with equation 2:
{3 X - 2 Y = 2 | (equation 1)
{X - 2 Y = -2 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 X - 2 Y = 2 | (equation 1)
{0 X - (4 Y)/3 = (-8)/3 | (equation 2)
Multiply equation 2 by -3/4:
{3 X - 2 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Add 2 × (equation 2) to equation 1:
{3 X+0 Y = 6 | (equation 1)
{0 X+Y = 2 | (equation 2)
Divide equation 1 by 3:
{X+0 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Collect results:
Answer: {X = 2 , Y = 2
My bad VectorFundament20, sheesh
Answer:
y=10x
Step-by-step explanation:
So y is basically 10 times x because each y value, 10, 20, 30 is coming from multiplying the x value by 10. For example, 0 = 10* 0, 10 = 10*1, 20 = 10*2, 30 = 10*3.
<span>x = -2.375 Hopefully that helps :)</span>