Answer:
the number of laps in the case when he run for 50 minutes is 18,333.33
Explanation:
The computation of the number of laps in the case when he run for 50 minutes is shown below:
Given that
He runs 440m lap in 1.2 minutes
So in 50 minutes he can have laps of
= 440 × 50 ÷ 1.2
= 18,333.33 laps
hence, the number of laps in the case when he run for 50 minutes is 18,333.33
Zn (s) -> Zn+2 (aq) + 2e-
Zn (s) with a neutral charge is oxidized and looses two electrons in the process to form ZnCl2 (aq) where Zn has a charge of 2+.
Answer:
buggy cyh gu hcgcggcfgggh5677
At STP volume is 22.4 L
Molar mass NO₂ = 46.0 g/mol
1 mole ---------- 22.4 L
? mole ---------- 11.4 L
moles = 11.4 * 1 / 22.4
moles = 11.4 / 22.4
= 0.5089 moles of NO₂
Mass NO₂ :
moles NO₂ * molar mass
0.5089 * 46.0
= 23.4094 g of NO₂
hope this helps!
