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Maslowich
3 years ago
7

Which of the following statements is true?

Chemistry
2 answers:
Marta_Voda [28]3 years ago
7 0

Answer:

is there an all of them are true option cause it should be that

Explanation:

kodGreya [7K]3 years ago
6 0

your answer to your question is all of the above

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How long will it take a piece of strontium-90 (produced in a nuclear test blast) weighing exactly 1000.0 g to be
Nonamiya [84]

Answer:

Time taken 172.8 years

Explanation:

Given data:

Total amount of strontium-90 = 1000.0 g

Amount left = 15.625 g

Half life of strontium = 28.8 years

Time taken = ?

Solution:

Number of half lives:

At time zero = 1000.0 g

At first half life = 1000.0g/2 = 500 g

At second half life = 500 g/2 = 250 g

At third half life = 250 g/ 2 = 125 g

At 4th half life = 125 g/ 2= 62.5 g

At 5th half life = 62.5 g/2 = 31.25 g

At 6th half life = 31.25 g / 2 = 15.625 g

Time taken:

Time taken = number of half lives × half life

Time taken = 6×28.8 years

Time taken = 172.8 years

7 0
3 years ago
I need some good help ​
Alexeev081 [22]

Answer:

lol

Explanation:

4 0
3 years ago
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Liquid 1 has a density of 2.0 g/ml, Liquid 2
Natali5045456 [20]

Liquid 2 because the lower the density the more it floats and the higher the density the more it sinks. The order from top to bottom is liquid 2, liquid 3, liquid 1

8 0
3 years ago
0.47 M KNO3 solution contains .757475 mol of KNO3 what is the volume
vfiekz [6]

Answer:

Volume is the quantity of three-dimensional  

Explanation:

7 0
3 years ago
How many grams of H2O are produced when 35.0 g of NaOH reacts with 17.5 g of CO,?
zhenek [66]

Answer:

2NaOH + CO2 -> Na2CO3 + H2O

1) Find the moles of each substance

\eq n(NaOH)=\frac{35.0}{22.99+16.00+1.008\\}\  =\frac{35.0}{39.998} \ = 0.8750437522 moles\\n(CO_{2} ) = \frac{17.5}{12.01+32.00} = \frac{17.5}{44.01} = 0.3976369007 moles\\

2) Determine the limitting reagent

\\NaOH = \frac{0.8750437522}{2} = 0.4375218761\\\\

∴ Carbon dioxide is limitting as it has a smaller value.

3) multiply the limiting reagent by the mole ratio of unknown over known

n(H2O ) = 0.3976369007 × 1/2

             = 0.1988184504 moles

4) Multiply the number of moles by the molar mass of the substance.

m = 0.1988184504 × (1.008 × 2 + 16.00)

   = 0.1988184504 × 18.016

   = 3.581913202 g

Explanation:

6 0
3 years ago
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