3 years ago

Which of the following statements is true?

Chemistry

2 answers:

Marta_Voda [28]3 years ago

7 0

Answer:

is there an all of them are true option cause it should be that

Explanation:

kodGreya [7K]3 years ago

6 0

your answer to your question is all of the above

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How many moles in 3.69 x 10^30 molecules of carbon dioxide?

elixir [45]

Answer:

four million two hundred and thirty

Explanation:

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3 years ago

What will the ph be in a titration of acetic acid and sodium hydroxide that is half way to equivalence point ?

ASHA 777 [7]

It would be 7 because the acid and base cancel out each other

8 0

3 years ago

Which of the following has the LOWEST electronegativity?<br> A) As<br> B) N<br> C) BI<br> D) P

ohaa [14]

N just use a electronegativity table

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3 years ago

What is the mass of hydrogen in 5.5 mol of Ca(OH)2?

Morgarella [4.7K]

Answer:

12*2*6.022*10^23. Atoms of hydrogen.

Explanation:

First of all if u know that 1 molecule of calcium hydroxide contain 2 hydrogen atom and 1 mole of calcium hydroxide contain 6.022*10^23 molecules of calcium hydroxide.

Hence 1 mole of calcium hydroxide contain 2*6.022*10^23 atom of hydrogen.

So 12 mole of calcium hydroxide contain =12*2*6.022*10^23. Atoms of hydrogen.

3 0

3 years ago

When 0.0901 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. I

Alexus [3.1K]

Answer:

The heat of combustion for the unknown hydrocarbon is -29.87 kJ/mol

Explanation:

Heat capacity of the bomb calorimeter = C = 1.229 kJ/°C

Change in temperature of the bomb calorimeter = ΔT = 2.19°C

Heat absorbed by bomb calorimeter = Q

$Q=C\times \Delta T$

$Q=1.229 kJ/^oC\times 2.19^oC=2,692 kJ$

Moles of hydrocarbon burned in calorimeter = 0.0901 mol

Heat released on combustion = Q' = -Q = -2,692 kJ

The heat of combustion for the unknown hydrocarbon :

$\frac{Q'}{0.090 mol}=\frac{-2,692 kJ}{0.0901 mol}=-29.87 kJ/mol$

6 0

3 years ago

Read 2 more answers