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1 year ago

Why does atomic radii decrease as you move from the left to right across the period

2 answers:

6 0

When we move from left to right across the periodic table, we can see that the atomic radii keeps decreasing. This is because, as you move from left to right, the nucleus gains protons. The atomic number increases and hence the valence electron will feel more attracted towards the nucleus & the atomic radii will decrease.

$\mathbb{MIREU}$

artcher [175]1 year ago

5 0

Answer:

This is because, within a period or family of elements, all electrons are added to the same shell.

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Answer:

yes it is true they apply necessary safety measures

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2 years ago

Potential energy is based on an objects

erma4kov [3.2K]

This is some information about the potential energy.

Explanation:

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2 years ago

Read 2 more answers

Rank the members of each set of compounds according to the ionic character of their bonds. Most ionic bonds?a) PCl3 PBr3 PF3 Mos

SCORPION-xisa [38]

Explanation:

More is the electronegativity difference between the combining atoms more polar is the compound. Hence, more ionic it will be in nature.

(a) Electronegativity value of P = 2.19

Electronegativity value of Cl = 3.16

Electronegativity value of Br = 2.96

Electronegativity value of F = 3.98

Electronegativity difference of a P-Cl bond = 3.16 - 2.19 = 0.97

Electronegativity difference of a P-Br bond = 2.96 - 2.19 = 0.77

Electronegativity difference of a P-F bond = 3.98 - 2.19 = 1.79

Since, a P-F bond has the highest electronegativity difference. Therefore, $PF_{3}$ is the most ionic compound and $PBr_{3}$ is the least ionic compound.

(b) Electronegativity value of B = 2.04

Electronegativity value of N = 3.04

Electronegativity value of C = 2.55

Electronegativity value of F = 3.98

Electronegativity difference of a B-F bond = 3.98 - 2.04 = 1.94

Electronegativity difference of a N-F bond = 3.04 - 3.98 = 0.94

Electronegativity difference of a C-F bond = 3.98 - 2.55 = 1.43

Since, a B-F bond has the highest electronegativity difference. Therefore, $BF_{3}$ is the most ionic compound and $NF_{3}$ is the least ionic compound.

(c) Electronegativity value of Se = 2.55

Electronegativity value of Te = 2.1

Electronegativity value of Br = 2.96

Electronegativity value of F = 3.98

Electronegativity difference of a Se-F bond = 3.98 - 2.55 = 1.43

Electronegativity difference of a Te-F bond = 3.98 - 2.1 = 1.88

Electronegativity difference of a Br-F bond = 3.98 - 2.19 = 1.02

Since, a Te-F bond has the highest electronegativity difference. Therefore, $TeF_{4}$ is the most ionic compound and $BrF_{3}$ is the least ionic compound.

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2 years ago

“Conductor, circuit breaker, switch” use the words provided to write the function of fuses.

bezimeni [28]

Answer:

The fuse is a thin wire that is the conductor of electricity is designed to breaks the circuit if there is a fault in an appliance that causes excessive current to flow in a circuit.

The conductor used in the fuse is melt and separated in such cases of excessive current in a circuit and switch the current off.

A circuit breaker is made up of a thin wire that is specially designed to switch that automatically breaks circuit current in the overcurrent condition.

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2 years ago

What is the daughter nucleus produced when 188 Hg Hg188 undergoes positron emission? Replace each question mark with the appropr

Alenkasestr [34]

Answer: The daughter nucleus produced when 188 Hg undergoes positron emission is gold.

Explanation:

Positron emission: It is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. This is also known as -decay. In this the mass number remains same.

General representation of an element is given as: $_Z^A\textrm{X}$

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

The chemical equation for positron emission is represented as:

$_Z^A\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0e$

$_{80}^{188}\textrm{Hg}\rightarrow _{79}^{188}\textrm{Au}+_{+1}^0e$

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2 years ago