The noble gas is Xenon and its molar mass is 131 g/mol.
<h3>What is the molar mass of the noble gas?</h3>
The molar mass of the noble gas is determined as follows;
Let molar mass of unknown gas be M, and mass of gas be m
Density of the noble gas, ρ = 5.8 g/dm³
density = m/V
At STP;
- temperature, T = 273.15 K
- pressure, P = 1 atm
- molar gas constant, R = 0.0821 L.atmK⁻¹mol⁻¹
From ideal gas equation:
PV = nRT
where n = m/M
PV = mRT/M
M = mRT/PV
M = 0.0821 * 273.15 * 5.84/1
Molar mass of the noble gas = 131 g/mol
The noble gas is Xenon which has molar mass approximately equal to 131 g/mol.
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Answer:
Specific heat of solid A is greater than specific heat of solid B.
Explanation:
In the calorimeter, as the temperature is increasing, the vibrational kinetic energy will increase and this means that additional amount of energy will be needed to increase the temperature by the same value. Therefore, we can conclude that specific heat increases as temperature increases.
Now, we are told that the final temperature of solid A's calorimeter is higher than that of B.
This means from our definition earlier, Solid A will have a higher specific heat that solid B.
I believe this question has the following five choices to
choose from:
>an SN2 reaction has occurred with inversion of
configuration
>racemization followed by an S N 2 attack
>an SN1 reaction has taken over resulting in inversion
of configuration
>an SN1 reaction has occurred due to carbocation
formation
>an SN1 reaction followed by an S N 2 “backside”
attack
The correct answer is:
an SN1 reaction has occurred due to carbocation formation
Answer:
Dos quintos al cuadrado dividido cinco medios a la menos 1.
Explanation:
<h3>
Answer:</h3>
22.41 seconds longer
<h3>
Explanation:</h3>
- Sound is a longitudinal wave that requires a material medium for transmission hence called a mechanical wave.
- Examples of medium in which sound travels in are water and air.
From the question give;
Speed of sound in air at 20°C is 343 m/s
Speed of sound in water at 20°C is 1,483 m/s
We are given a distance of 10 Km or 10,000 m
We need to finder how much longer it will take for the sound to travel in air.
Time = Distance ÷ Speed
Therefore;
Time taken in Air = Distance ÷ speed of sound in air
= 10000 m ÷ 343 m/s
= 29.15 seconds
Time taken in water = Distance ÷ speed of sound in water
= 10,000 ÷ 1,483 m/s
= 6.74 seconds
Difference in time = 29.15 seconds - 6.74 seconds
= 22.41 seconds
Therefore, it takes 22.41 seconds longer for sound to travel through air than water.
