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mariarad [96]
3 years ago
15

Which two-dimensional figure could be a cross section of a rectangular pyramid that has been intersected by a plane perpendicula

r to its base and through its vertex?
Mathematics
1 answer:
DanielleElmas [232]3 years ago
7 0
The choices are found elsewhere and the figures would be:
a. rectangleb. trianglec. squared. trapezoid
From the choices, the answer would be option B. A triangle figure would be the cross section when <span>a rectangular pyramid that has been intersected by a plane perpendicular to its base and through</span>its vertex.
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Hannah and andrea were selling tickets to the homecoming dance. they were set up in different
coldgirl [10]

The relationship between the number of tickets is that Hannah sold three times as many tickets as Andrea.

<h3>How to determine the relationship?</h3>

From the question, we have:

Andrea = h

Hannah = 3h

This means that:

Hannah = 3 * Andrea

So, the relationship is that Hannah sold three times as many tickets as Andrea.

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brainly.com/question/4344214

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5 0
2 years ago
Wich tool is used to measure the lengths of segments when preforming a formal geometric construction
Dmitrij [34]

A ruler as that is the only option that can measure segments

5 0
3 years ago
PLEASE HELP ITS DUE TODAYYY
Bumek [7]

Answer:

(-3,10) (0,5) (3,0) (6,-5)

Step-by-step explanation:

x intercept = 3

y intercept =5

If brainiest is earned its greatly appreciated

6 0
3 years ago
An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen
devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = \frac{\sum X}{n} = 441

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 14.34

            n = sample size = 16

            \mu = population mean

<em>Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<em />

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.131 < t_1_5 < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.131) = 0.95

P( -2.131 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.131 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X -2.131 \times {\frac{s}{\sqrt{n} } } , \bar X +2.131 \times {\frac{s}{\sqrt{n} } } ]

                                      = [ 441-2.131 \times {\frac{14.34}{\sqrt{16} } } , 441+2.131 \times {\frac{14.34}{\sqrt{16} } } ]

                                      = [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0
3 years ago
Which expression is equalivalent to 2( t-4) + 1
Veronika [31]

Answer:

It's gonna be 2t - 7 my friend

Step-by-step explanation:

8 0
2 years ago
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