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Alchen [17]
3 years ago
15

What is the oxidation state of the underlined atom in the reaction:

Chemistry
1 answer:
kvasek [131]3 years ago
6 0

Answer:

+5

Explanation:

Let's consider the following balanced equation.

Mn(NO₃)₂ + 2 HCl --> MnCl₂ + 2 HNO₃

We can determine the oxidation number of N in (NO₃)₂²⁻ taking into account that the sum of the oxidation numbers of the elements present in a chemical species is equal to this overall charge. For this compound we know:

  • The oxidation number of O is -2.
  • The overall charge is 2-.
  • We have 2 atoms of N and 2× 3 = 6 atoms of O.

2 N + 6 O = 2-

2 N + 6 (-2) = 2-

2 N = +10

N = +5

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Which neutral atom is isoelectronic with N-3?
Airida [17]

Answer:

The trick here is to realize that the nitride anion, N3− , is isoelectronic with neon, Ne , the noble gas that shares a period with nitrogen, N . In other words, the nitride anion has the same number of electrons as neon.J

Explanation:

5 0
2 years ago
Put the following elements in order of increasing atomic number:
melisa1 [442]

Answer:

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5 0
3 years ago
Calculate the mass of 0.5dm3 of a 2g/dm3 solution of silver nitrate
cupoosta [38]

Answer:

5.6

Explanation:

Because of the gravity of the earth

6 0
3 years ago
A person of 82 kg is in an elevator. If the elevator is moving at a speed of 5m/s, what’s the person’s kinetic energy.
andre [41]

Answer:

The person’s kinetic energy is 1,025 J

Explanation:

Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.

Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and in a position of rest, until it reaches a given speed. Once this point is reached, the amount of accumulated kinetic energy will remain the same unless there is a change in speed or the body returns to its state of rest by applying a force.

Kinetic energy is represented by the following formula:

Ec=\frac{1}{2}*m*v^{2}

where Ec is kinetic energy, which is measured in Joules (J), m is mass measured in kilograms (kg), and v is velocity measured in meters over seconds (m/s).

In this case:

  • Ec= ?
  • m= 82 kg
  • v= 5 \frac{m}{s}

Replacing:

Ec=\frac{1}{2}*82 kg*(5\frac{m}{s} )^{2}

Solving:

Ec= 1,025 J

<u><em>The person’s kinetic energy is 1,025 J</em></u>

3 0
3 years ago
A mixture of methane gas, CH4(g) , and pentane gas, C5H12(g) , has a pressure of 0.5239 atm when placed in a sealed container. T
vovikov84 [41]

Answer:0.86

Explanation:

A mixture of methane gas, CH4(g), and pentane gas, C5H12(g), has a pressure of 0.5922 atm when placed in a sealed container.Lets suppose initially partial pressure of CH4 is x and C5H12 is y

x+y=0.5922-----i

1.CH4[g] + 2O2[g] -> CO2[g] + 2 H2O[g]

2.C5H12 + 8O2 → 5CO2 + 6H2O

partial pressure of CH4 is x produce xatm of CO2 and 2xatm of H2O

x + 2x = 3 atm

partial pressure of C5H12 is y produce 5yatm of CO2 and 6yatm of H2O

5y+6y=11y

so the final partial pressure of product mixture will be

3x + 11y = 2.429atm ------ii

solve eq i for x and put in ii

x=0.5922-y -----iii

3(0.5922-y)+ 11y = 2.429atm

y= 0.8155atm

put in iii

x=0.5922-0.8155

x= 0.51atm (Partial pressure of CH4)

mol fraction of CH4=Partial pressure/

Total pressure

=0.51/0.5922

=0.86.

4 0
4 years ago
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