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Studentka2010 [4]
3 years ago
5

Which of the following is an example of observational scientific investigation?

Chemistry
2 answers:
Softa [21]3 years ago
8 0
B: nothing the color of the solution when heated
hoa [83]3 years ago
5 0

Answer:

The correct answer will be option-B.

Explanation:

A scientific investigation involves many steps to answer and explain the natural phenomenon.  The observational scientific investigation is a way which includes making an observation which is also the first step of the scientific method.

In the given question, observing the color of the solution while heating will be considered as an example of observational investigation as it states that something has been observed with the senses of the human. All other are cases of experimental investigation.

Thus, Option-B is the correct answer.

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If 20.0 grams of Na reacts with 30.0 gtams of Cl2 what mass of NaCl is produfed by the reaction
IgorLugansk [536]

Answer:

mNaCl = mNa + mCl

mNa = 20g

mCl = mCl2/2 = 30/2 = 15g

mNaCl= 20+15 = 35g

6 0
1 year ago
The state of matter that has molecules with the least random molecular arrangement:
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Gas. Molecules in gas are able to move and vibrate around each other more freely than the molecules in liquids and/or solids due to the great amount of space in between them. Hope this helps! :)
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What is the KE of 750 kg car moving at 25 m/s?
Ymorist [56]

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3 years ago
A heterogeneous material may be
IgorLugansk [536]

Answer:

4) a mixture.....................

7 0
2 years ago
Read 2 more answers
(c) O2 gas is transferred from a 3 L vessel containing oxygen at 4 atm to an evacuated 20 L vessel at a constant temperature of
Fudgin [204]

Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

P x V = k

Therefore, for this problem the step by step explanation is:

P_{1} xV_{1} = P_{2} xV_{2}

Clearing P2 and replacing

P_{2}= \frac{P_{1} xV_{1}}{V_{2} } = \frac{4atmx3L}{20L} = 0.6atm

7 0
3 years ago
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