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Studentka2010 [4]
3 years ago
5

Which of the following is an example of observational scientific investigation?

Chemistry
2 answers:
Softa [21]3 years ago
8 0
B: nothing the color of the solution when heated
hoa [83]3 years ago
5 0

Answer:

The correct answer will be option-B.

Explanation:

A scientific investigation involves many steps to answer and explain the natural phenomenon.  The observational scientific investigation is a way which includes making an observation which is also the first step of the scientific method.

In the given question, observing the color of the solution while heating will be considered as an example of observational investigation as it states that something has been observed with the senses of the human. All other are cases of experimental investigation.

Thus, Option-B is the correct answer.

You might be interested in
A scientific law is ___.
Daniel [21]

Answer: a rule that describes a pattern in nature.

Explanation:

3 0
2 years ago
How many grams of aluminum are required to give a total dislocation length of 3,000 miles (enough to stretch from New York City
Luba_88 [7]

Answer:

0.13 g

Explanation:

mass of aluminum required = ( Dislocation length) / ( Dislocation density) × (density of metal)

3000 miles to cm (  1 mile = 160934 cm) = 3000 miles ×  160934 cm / 1 mile = 482802000 cm

density of Aluminium = 2.7 g /cm³

dislocation density of aluminum = 10¹⁰ cm³

mass of aluminum required = (482802000 cm × 2.7 g/cm³) / 10¹⁰ cm³ = 0.13 g

5 0
3 years ago
A 13-gram rubber stopper is attached to a 0.93-meter
makkiz [27]
<h3>Answer:</h3>

The centripetal acceleration is 26.38 m/s²

<h3>Explanation:</h3>

We are given;

  • Mass of rubber stopper = 13 g
  • Length of the string(radius) = 0.93 m
  • Time for one revolution = 1.18 seconds

We are required to calculate the centripetal acceleration.

To get the centripetal acceleration is given by the formula;

Centripetal acc = V²/r

Where, V is the velocity and r is the radius.

Since time for 1 revolution is 1.18 seconds,

Then, V = 2πr/t, taking π to be 3.142 ( 1 revolution = 2πr)

Therefore;

Velocity = (2 × 3.142 × 0.93 m) ÷ 1.18 sec

             = 4.953 m/s

Thus;

Centripetal acceleration = (4.953 m/s)² ÷ 0.93 m

                                        = 26.38 m/s²

Hence, the centripetal acceleration is 26.38 m/s²

6 0
3 years ago
What is the answer? show proof I will report you if you answer for the points​
IceJOKER [234]

Answer:

A

Explanation:

carbon dioxide is released in cellular respiration

3 0
2 years ago
What several factors help the veins push blood back to the heart
Tomtit [17]
A)Constant pumping from the heart which provides adequate pressure necessary to move the blood through the arteries and veins
B)Gravitational force
6 0
3 years ago
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