Answer:
ω' = 0.815 rad/s
Explanation:
Given,
R = 1.20 m
Inertia of merry-go- round= 240 kg.m²
Rotating speed = 9 rpm = 
=0.9424 rad/s
mass of the child, m = 26 kg
angular speed of the merry-go-round=?
we know
Angular momentum, L = I ω
Moment of inertia of the child
I' = m r² = 26 x 1.2² = 37.44 kgm²
Conservation of angular momentum
initial angular momentum = Final angular momentum
I ω = (I+I')ω'
240 x 0.9424 = (240+37.44) ω'
226.176= 277.44 ω'
ω' = 0.815 rad/s
new angular speed of the merry-go- round is equal to 0.815 rad/s
I’m guessing b because hydrogen is in your room and maybe eliminate to o but it also can be D
my final is: B!
Answer:
5.5 × 10-2 hertz
Explanation:
The time taken by a wave crest to travel a distance equal to the length of wave is known as wave period.
= 0.055 per second (1 cycle per second = 1 Hertz)
Thus, we can conclude that the frequency of the wave is 5.5 X 10^{-2} hertz.
Hopes this helps, love <3
Reservoir i think. i’m not sure
Answer:
as shown in the attached file.
Explanation:
The detailed step by step approach by the application of the expression for the parallel plate capacitor and appropriate substitution to ge the number of electrons added or removed is as shown in the attachment.
