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____ [38]
3 years ago
13

A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When re

leased the spring toy pops up and reaches a maximum height of 1.5 meters.
1) How much elastic potential energy is initially stored in the spring?


2)How much internal energy is produced as the toy springs up to its maximum height?
Physics
1 answer:
forsale [732]3 years ago
8 0

Answer:

(1) V = 0.2 J (2) 0.05J

Explanation:

Solution

Given that:

K = 160 N/m

x = 0.05 m

Now,

(1) we solve for the  initial potential energy stored

Thus,

V = 1/2 kx² = 0.5 * 160 * (0.05)²

Therefore V = 0.2 J

(2)Now, we solve for how much of the internal energy is produced as the toy springs up to its maximum height.

By using the energy conversion, we have the following

ΔV = mgh

=(0.1/9.8) * 9.8 * 1.5 = 0.15J

The internal energy = 0.2 -0.15

=0.05J

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Answer:

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B. Resistance.

Explanation:

According to ohms law   " the current  passing through a conductor is directly proportional to the potential difference between the ends provided the temperature of the wire remains constant".

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Structures on a bird feather act like a diffraction grating having 7000 7000 lines per centimeter. What is the angle of the firs
Anestetic [448]

Answer:

θ = 28.9°

Explanation:

We are given;

Wavelength; λ = 602nm = 602 x 10^(-9) m

Lines per centimetre = 7000 /cm = 700000 /m

Thus, the distance between 2 adjacent lines is;

d = 1/700000 = 1.43 x 10^(-6) m

The angle at which diffracted light is formed is given by the formula

mλ = d sinθ

Where;

m is the mth order of the diffraction

λ is the wavelength of the incident light

d is the distance separating the centres of 2 adjacent slits

θ is the angle at which diffraction occurs

From the question, m is 1 because it says first order.

Thus, plugging in the relevant values into mλ = d sinθ, we have;

1 x 602 x 10^(-9) = 1.43 x 10^(-6) sinθ

sinθ = 602 x 10^(-9)/(1.43 x 10^(-6))

sinθ = 0.42098

θ = sin^(-1) 0.42098

θ = 28.9°

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grin007 [14]

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In this image of Earth and the Moon from the Sim, what does the circle around Earth represent?
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An orbit is a circular/oval path that planets, moons, comets, etc follow with a "subject" in the middle. In this case, the circle is the orbit of the moon around Earth.

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The summary of the given statement is explained below throughout the explanation segment.

Explanation:

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