Use a sum or difference identity to evaluate.<br><br> sin15∘

A right triangle has leg lengths of 9 units and 12 units. Write an equation that can be

LenKa [72]

<h2>The Pythagorean Theorem</h2>

The Pythagorean Theorem: $a^2+b^2=c^2$

<em>a</em> and <em>b</em> are the two legs in a right triangle
<em>c</em> is the hypotenuse (the longest side of a right triangle; opposite the 90° angle
<em>*keep in mind that this theorem applies only to right triangles</em>

<h2>Solving the Question</h2>

We're given:

Legs = 9 units and 12 units
Hypotenuse = <em>c</em>

<em />

Plug these measurements into the Pythagorean theorem:

$a^2+b^2=c^2\\9^2+12^2=c^2$

⇒ Combine like terms:

$81+144=c^2\\c^2=225$

<h2>Answer</h2>

$c^2=225$

4 0

2 years ago

How you can know a fraction is equivalent to another fraction

Alex73 [517]

The denominator. Say for instance, you have 4/12 and 1/6. They are equivalent.

6 0

3 years ago

Read 2 more answers

Which number produces an irrational number when multiplied by 1/3

MArishka [77]

We can simply observe that.

0.777... is rational, because it is a number with infinite but repeating decimal part.
1/3 is rational, because it's the division between two integers
$-\sqrt{16}=-4$ , so this is rational as well.

Since the product of two rational numbers is always rational, we have that

$0.\bar{7}\cdot \dfrac{1}{3},\quad \dfrac{1}{3}\cdot \dfrac{1}{3},\quad -4\cdot \dfrac{1}{3}$

are all rationals, since they are the product of two rationals.

On the other hand, we have

$\sqrt{27}=\sqrt{9\cdot 3}=3\sqrt{3}$

and thus

$3\sqrt{3}\cdot \dfrac{1}{3}=\sqrt{3}$

which is irrational.

3 0

3 years ago

Who's faster a dog or a fish plz help me

VashaNatasha [74]

Answer:

fish

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Refer to the following scenario:You want to see if there is a difference between the exercise habits of Science majors and Math

bekas [8.4K]

Answer:

1. H0: P1 = P2

2. Ha: P1 ≠ P2

3. pooled proportion p = 0.542

4. P-value = 0.0171

5. The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

6. The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

Step-by-step explanation:

We should perform a hypothesis test on the difference of proportions.

As we want to test if there is significant difference, the hypothesis are:

Null hypothesis: there is no significant difference between the proportions (p1-p2 = 0).

Alternative hypothesis: there is significant difference between the proportions (p1-p2 ≠ 0).

The sample 1 (science), of size n1=135 has a proportion of p1=0.607.

$p_1=X_1/n_1=82/135=0.607$

The sample 2 (math), of size n2=92 has a proportion of p2=0.446.

$p_2=X_2/n_2=41/92=0.446$

The difference between proportions is (p1-p2)=0.162.

$p_d=p_1-p_2=0.607-0.446=0.162$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{82+41}{135+92}=\dfrac{123}{227}=0.542$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.542*0.458}{135}+\dfrac{0.542*0.458}{92}}\\\\\\s_{p1-p2}=\sqrt{0.001839+0.002698}=\sqrt{0.004537}=0.067$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.162-0}{0.067}=\dfrac{0.162}{0.067}=2.4014$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$\text{P-value}=2\cdot P(z>2.4014)=0.0171$

As the P-value (0.0171) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

We want to calculate the bounds of a 99% confidence interval of the difference between proportions.

For a 99% CI, the critical value for z is z=2.576.

The margin of error is:

$MOE=z \cdot s_{p1-p2}=2.576\cdot 0.067=0.1735$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.162-0.1735=-0.012\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.162+0.1735=0.335$

The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

6 0

3 years ago

Use a sum or difference identity to evaluate. sin15∘