1) Area = (b*h)/2 = (9*5)/2 = 45/2 = 22.5 (Letter A)
2) Area = b*h = 8*14 = 112 (Letter D)
3) Surface area of a prism is SA=2B+ph (B = area of the base, p = perimeter of the base, h = height)
B = 15 * 5 = 75 cm^2
p = 15 + 5 = 20 cm
SA = 2*75 + 20*7 = 150 + 140 = 290 (G)
4) V = (B*H*L)/2 = (15*7*5)/2 = 525/2 = 262.5 cm^3 (G)
5) V = 9^3 = 81 cm^3 worth of wrapping (A)
6) V = (B*H*L)/2 = (13*6*8)/2 = 312 cube feet (J)
It gave me ADGGAJ. I don't know if this is right, but I atleast tried to do something, right?
Ok so your first step is to make this an equation
she gets paid x amount per hour and she works for 22 hours
so 22x plus her bonus
22x + 500 =1204
so now solve the equation
subtract both sides by 500
22x +500 =1204
-500 = -500
to get
22x = 704
now divide both sides by 22
x = 32
mrs jackson worked 32 hours to get her pay check
Answer:
1516
Step-by-step explanation:
hope can help you
2000x 2%=40
9000x 5%= 450
(30000-9000-2000) x 5.4% = 1026
total tas 40+450+1026=
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
----> inequality A
solve for y


The solution of the inequality A is the shaded area above the dashed line
The slope of the dashed line is positive
The y-intercept is the point 
The x-intercept is the point 
----> inequality B
The solution of the inequality B is the shaded area below the dashed line
The slope of the dashed line is positive
The y-intercept is the point 
The x-intercept is the point 
Using a graphing tool
The solution of the system of inequalities in the attached figure
Answer:
A.) gf(x) = 3x^2 + 12x + 9
B.) g'(x) = 2
Step-by-step explanation:
A.) The two given functions are:
f(x) = (x + 2)^2 and g(x) = 3(x - 1)
Open the bracket of the two functions
f(x) = (x + 2)^2
f(x) = x^2 + 2x + 2x + 4
f(x) = x^2 + 4x + 4
and
g(x) = 3(x - 1)
g(x) = 3x - 3
To find gf(x), substitute f(x) for x in g(x)
gf(x) = 3( x^2 + 4x + 4 ) - 3
gf(x) = 3x^2 + 12x + 12 - 3
gf(x) = 3x^2 + 12x + 9
Where
a = 3, b = 12, c = 9
B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)
To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula
Y = 3x + 3
X = 3y + 3
Make y the subject of formula
3y = x - 3
Y = x/3 - 3/3
Y = x/3 - 1
Therefore, g'(x) = x/3 - 1
For g'(12), substitute 12 for x in g' (x)
g'(x) = 12/4 - 1
g'(x) = 3 - 1
g'(x) = 2.