the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
4'9.87
Step-by-step explanation:
Answer:
true
Step-by-step explanation:
Answer: 6 = 2(1+2), this is true.
Step-by-step explanation:
To solve this, 6 = 2(1 +2) =
This question is to proove that 2(1 +2) = 6
First we open the bracket:
(2 × 1) + (2 × 2)
Multiply 2 by 1 = 2
Multiply 2 by 2 = 4
2 + 4 = 6
I hope this helps.
