Compare and contrast potential and kinetic energy

2 answers:

7 0

Kinetic and Potential Energy HistoryA roller coaster train going down hill represents merely a complex case as a body is descending an inclined plane. Newton's first two laws relate force and acceleration, which are key concepts in roller coaster physics. At amusement parks, Newton's laws can be applied to every ride. These rides range from 'The Swings' to The 'Hammer'. Newton was also one of the developers of calculus which is essential to analyzing falling bodies constrained on more complex paths than inclined planes. A roller coaster rider is in an gravitational field except with the Principle of Equivalence.Potential EnergyPotential energy is the same as stored energy. The "stored" energy is held within the gravitational field. When you lift a heavy object you exert energy which later will become kinetic energy when the object is dropped. A lift motor from a roller coaster exerts potential energy when lifting the train to the top of the hill. The higher the train is lifted by the motor the more potential energy is produced; thus, forming a greater amount if kinetic energy when the train is dropped. At the top of the hills the train has a huge amount of potential energy, but it <span>has very little kinetic energy.Kinetic Energy The word "kinetic" is derived from the Greek word meaning to move, and the word "energy" is the ability to move. Thus, "kinetic energy" is the energy of motion --it's ability to do work. The faster the body moves the more kinetic energy is produced. The greater the mass and speed of an object the more kinetic energy there will be. Hope this helped:))))</span>

mariarad [96]3 years ago

3 0

Kinetic Energy is moving energy. And potential energy is air G that has the potential to be movie or not moving at all

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Learning Goal: To practice Problem-Solving Strategy 30.1 Electromagnetic Induction. A coil of wire contains N turns and has an e

Helen [10]

Answer:

Time interval for which magnetic field reduced to ZERO is given as

$t = \frac{NB_0\pi a^2}{RI}$

Explanation:

As we know that the flux linked with one coil is given as

$\phi = B_0 A$

$\phi = B_0(\pi a^2)$

now total flux of all coils is given as

$\phi = NB_0\pi a^2$

now let say the flux is reduced to ZERO after time "t"

so as per Faraday's law EMF induced in the coil is given as

$EMF = \frac{NB_0\pi a^2 - 0}{t}$

now the current in the coil is given as

$I = \frac{EMF}{R}$

$I = \frac{NB_0\pi a^2}{Rt}$

so the time interval is given as

$t = \frac{NB_0\pi a^2}{RI}$

8 0

3 years ago

A proton starts from rest near the surface of a sheet of charge. It experiences a force of 14.0 microNewtons towards the sheet.

Naddika [18.5K]

Answer:

The surface charge density of the sheet is 1547.516 C/m²

Explanation:

Given;

force experienced by the proton, F = 14.0 μN

Electric field near an infinite sheet with surface charge density (σ) is given as;

E = σ/2ε₀

The force of attraction the proton experienced towards the sheet;

F = Eq

F = q(σ/2ε₀) $= \frac{q \sigma}{2 \epsilon_o}$

where;

q is the charge of the proton

σ is the surface charge density of the sheet

ε₀ is the permittivity of free space

$F = \frac{q \sigma}{2 \epsilon_o} \\\\\sigma = \frac{2F \epsilon_o}{q} \\\\\sigma = \frac{2*14*10^{-6}*8.854*10^{-12}}{1.602*10^{-19}} = 1547.516 \ C/m^2$