Mastering Problems
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Let's start from the Fluorine (F), which has 4 atoms on the right side: this means we must put a factor 4 in front of HF to balance the number of atoms of Fluorine.
Nowe we have 4 atoms of hydrogen, H, on the left side. Since we have a
on the right side (2 atoms), we must put a factor 2 in front of 
, to balance the number of atoms of hydrogen.
So now the atoms of oxygen are also balanced (2 on both sides), as well as the atoms of Silicon (Si), so the balanced reaction is
Nowe we have 4 atoms of hydrogen, H, on the left side. Since we have a
So now the atoms of oxygen are also balanced (2 on both sides), as well as the atoms of Silicon (Si), so the balanced reaction is
The final magnification will be 400-fold or 400 times the original size of the object.
For magnifying smaller objects, a compound microscope is used.
A compound microscope consists of an objective and an eyepiece, whose diagram is shown in the adjoining image.
The lens near the object is called an objective and the other one is the eyepiece.
Let the magnification of the objective be m1
Let the magnification of the eyepiece be m2
The final magnification by the microscope, M, will be
M = m1 x m2
Putting the values in the above equation
M = 40 x 10
M= 400
Thus, the final magnification will be 400-fold or 400 times the original size of the object.
To know more about "optical instruments", refer to the link given below:
brainly.com/question/13276240?referrer=searchResults\
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